Incomplete question. However, let's assume this are feasible regions to consider:
Points:
- (0, 100)
- (0, 125)
- (0, 325)
- (1, 200)
Answer:
<u>Maximum value occurs at 325 at the point (0, 325)</u>
<u>Step-by-step explanation:</u>
Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.
- For point (0, 100): P= 2(0) + 1.5 (100) =150
- For point (0, 125): P= 2(0) + 1.5 (125) =187.5
For point (0, 325): P= 2(0) + 1.5 (325) = 487.5
For point (1, 200): P= 2(1) + 1.5 (200) = 302
Therefore, we could notice from the above solutions that at point (0,325) we attain the maximum value of P.
Answer:
Step-by-step explanation:
associative property because the numbers are changing in postition throughout the equation.
Given:
The inequality is:
To find:
The y-intercept, slope and type of line (solid or dotted).
Solution:
The slope intercept form of a line is:
...(i)
Where, m is the slope and b is the y-intercept.
We have,
The relation equation is:
...(ii)
On comparing (i) and (ii), we get
It means the slope is 5 and the y-intercept is 3.
The sign of the inequality in the given inequality is ">". It means the boundary line is not included in the solution set. So, the boundary line is a dotted line.
Therefore, the slope is 5, the y-intercept is 3 and the line is a dotted line.
Answer:
The conclusion "T" logically follows from the premises given and the argument is valid
Step-by-step explanation:
Let us use notations to represent the steps
P: I take a bus
Q: I take the subway
R: I will be late for my appointment
S: I take a taxi
T: I will be broke
The given statement in symbolic form can be written as,
(P V Q) → R
S → (¬R ∧ T)
(¬Q ∧ ¬P) → S
¬R
___________________
∴ T
PROOF:
1. (¬Q ∧ ¬P) → S Premise
2. S → (¬R ∧ T) Premise
3. (¬Q ∧ ¬P) → (¬R ∧ T) (1), (2), Chain Rule
4. ¬(P ∨ Q) → (¬R ∧ T) (3), DeMorgan's law
5. (P ∨ Q) → R Premise
6. ¬R Premise
7. ¬(P ∨ Q) (5), (6), Modus Tollen's rule
8. ¬R ∧ T (4), (7), Modus Ponen's rule
9. T (8), Rule of Conjunction
Therefore the conclusion "T" logically follows from the given premises and the argument is valid.
The mean can be found by adding the two numbers and dividing by 2
let the second number be y
(x + y)/2 = 1/2x + 1
solve for y
multiply each side by 2
x + y = 2(1/2x + 1)
distribute
x + y = x + 2
subtract x on both sides
y = 2
ANSWER: the second number is 2
