Apply the distributive property to factor out the greatest common factor. 12+80=
1 answer:
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Answer:
Step-by-step explanation:
The mean SAT score is , we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it ) is
Next they draw a random sample of n=70 students, and they got a mean score (denoted by ) of
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis
- The alternative would be then the opposite
The test statistic for this type of test takes the form
and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.
Answer:
$210
Step-by-step explanation:
Cost of 44kg onions = $308
Cost of 1kg onion =
Cost of 30kg onions =
You can group first two conjunctions and second two:
.
In first brackets you have common
and in second brackets common is 5:
.
In first brackets you have common