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Harlamova29_29 [7]
3 years ago
13

Geometry question plz help

Mathematics
1 answer:
GarryVolchara [31]3 years ago
5 0

Answer:if it’s a pretest just guess you don’t need to get it right

Step-by-step explanation:

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Y= 4x-9 <br> and y=x-3 <br><br><br> Also using transitive property
Andreyy89
Y = 4x - 9 and y = x-3 so the two right sides (4x-9 and x-3) must be equal

4x-9 = x-3

Let's solve for x

4x-9 = x-3
4x-9+9 = x-3+9 ... add 9 to both sides
4x = x+6
4x-x = x+6-x ... subtract x from both sides
3x = 6
3x/3 = 6/3 ... divide both sides by 3
x = 2

If x = 2, then y is...
y = 4*x - 9 = 4*2-9 = 8-9 = -1
which can also be found by 
y = x-3 = 2-3 = -1

So overall x = 2 and y = -1

We have the ordered pair (x,y) = (2,-1)
4 0
3 years ago
Boris pays $3.84 for a bag of 16 tangerines.
Naily [24]
3.84/16 = 0.24 per tangerine
7 0
3 years ago
If you don’t know the answer don’t answer it pls help me out if you do tho!
antoniya [11.8K]

Answer: x = 8

Step-by-step explanation:

Hello again XD.

This is a coordinate plane and all the angles on a coordinate plane add up to 360°

Divide 360 by 4 to get the measurement of the section we are working in.

360/4 = 90°

This means it is complementary and complementary angles state that both separate angles added together = 90°

therefore,

6x + 2 + 40 = 90

combine like terms:

6x + 42 = 90

now subtract 42 from both sides

6x = 48

divide 6 from both sides to get:

x = 8

Let me know if you have any more questions you want answered and I hope I explained this well.

5 0
2 years ago
The general solution of 2 y ln(x)y' = (y^2 + 4)/x is
Sav [38]

Replace y' with \dfrac{\mathrm dy}{\mathrm dx} to see that this ODE is separable:

2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}

Integrate both sides; on the left, set u=y^2+4 so that \mathrm du=2y\,\mathrm dy; on the right, set v=\ln x so that \mathrm dv=\dfrac{\mathrm dx}x. Then

\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v

\implies\ln|u|=\ln|v|+C

\implies\ln(y^2+4)=\ln|\ln x|+C

\implies y^2+4=e^{\ln|\ln x|+C}

\implies y^2=C|\ln x|-4

\implies y=\pm\sqrt{C|\ln x|-4}

4 0
2 years ago
Area and explanation thanks
adoni [48]
Area of the rectangle is 18•3= 54
Area of the triangle is (10-3)•(18-6)/2= 7•12/2= 42
Area of the whole figure is 54+42=96
3 0
3 years ago
Read 2 more answers
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