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steposvetlana [31]
3 years ago
8

A box contains 3 red and 4 green marbles. If 5 marbles are drawn without replacement, what is the expected number of red marbles

Mathematics
1 answer:
blsea [12.9K]3 years ago
4 0

Answer:

i hope this helps i believe it is 1/3

2 is

Step-by-step explanation:

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Help me on this please and thank you
vovikov84 [41]

Answer: I'm prett sure its c) 60, 90, and 120

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
12 (x+1/6) = 8 20 points
Aliun [14]

Answer:

12x + 2

Step-by-step explanation:

12 is multiplyed by both the x and the (1/6) since it is outside the equation.

so 12 times x = 12x since we dont know what x is

and 12 times (1/6) = (12/6) = 2

7 0
3 years ago
Can someone help me please
vovikov84 [41]
X=7




Explanation:

A triangle equals 180°, and they gave us one length already, and it says the one arm of the triangle is equal to the other so we know that the third angle is going to be the same as the second angle.


180=90+(6x+3)+(6x+3)
Combine like terms
180=96+12x
Subtract 96 from both sides
84=12x
Divide 12 by both sides
7=x


Now check it,

90+(6*7+3)+(6*7+3)
90+(45)+(45) =180
8 0
3 years ago
Rewrite the product as a sum: 10cos(5x)sin(10x)
mote1985 [20]

Answer:

10cos(5x)sin(10x) =  5[sin (15x) + sin (5x)]

Step-by-step explanation:

In this question, we are tasked with writing the product as a sum.

To do this, we shall be using the sum to product formula below;

cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]

From the question, we can say α= 5x and β= 10x

Plugging these values into the equation, we have

10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]

= 5[sin (15x) - sin (-5x)]

We apply odd identity i.e sin(-x) = -sinx

Thus applying same to sin(-5x)

sin(-5x) = -sin(5x)

Thus;

5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]

= 5[sin (15x) + sin (5x)]

Hence,  10cos(5x)sin(10x) =  5[sin (15x) + sin (5x)]

8 0
3 years ago
Help with 2 questions please.
Natasha_Volkova [10]
1 is the 3rd option down
2 is the second option down

7 0
3 years ago
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