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irina [24]
3 years ago
6

Factor the quadratic expression completely 8x^2 + 6x - 5

Mathematics
1 answer:
alekssr [168]3 years ago
8 0
Answer: (4x+5) • (2x-1)



Explanation:


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In a video game, Charles scored -250 points on his second play this brought his total score to 500. What was his score on the fi
Lyrx [107]
His First Play Was 750 Points

(1st Play) 750 (second play) -250

750 - 250 = 500


4 0
3 years ago
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Line AB contains points A (0, 1) and B (1, 5). The slope of line AB is A. -4 B. -1/4 C. 1/4 D. 4
il63 [147K]
Slope is rise over run so since it rose 4 and went 1 to the right the slope would be 4 because 4/1=4 P.S. The actual formula for slope is y2-y1 over x2-x1 so it would be 5-1/1-0 which again is 4/1
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3 years ago
HELP ME PLS I DONT HAVE TIME
chubhunter [2.5K]

Answer:

A is true.......................b is false....................and c is false

Step-by-step explanation:

6 0
3 years ago
Which of the following equations has no solution?
daser333 [38]

Answer:

B. 3x+5−4x=−(x+8)

Explanation:

3x+5−4x=−(x+8)

Step 1: Simplify both sides of the equation.

3x+5−4x=−(x+8)

3x+5+−4x=−x+−8

(3x+−4x)+(5)=−x−8

−x+5=−x−8

−x+5=−x−8

Step 2: Add x to both sides.

−x+5+x=−x−8+x

5=−8

Step 3: Subtract 5 from both sides.

5−5=−8−5

0=−13

So, there is no solution

Hope this Helps!

8 0
3 years ago
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Ok whoever answers this correct will get 100 brainly points
Snezhnost [94]

Answer:

We are given an area and three different widths and we need to determine the corresponding length and perimeter.  

The first width that is provided is 4 yards and to get an area of 100 we need to multiply it by 25 yards.  This would mean that our length is 25 yards and our perimeter would be 2(l + w) which is 2(25 + 4) = 58 yards.

The second width that is given is 5 yards and in order to get an area of 100 yards we need to multiply by 20 yards.  This would mean that our length is 20 yards and our perimeter would be 2(l + w) which is 2(20 + 5) = 50 yards.

The final width that is given is 10 yards and in order to get an area of 100 yards we need to multiply by 10.  This would mean that our length is 10 yards and our perimeter would be 2(l + w) which is 2(10 + 10) = 40 yards.

Therefore the field that would require the least amount of fencing (the smallest perimeter) is option C, field #3.

<u><em>Hope this helps!</em></u>

3 0
2 years ago
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