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seraphim [82]
3 years ago
5

How do you put an equation in slope-intercept form into standard or point-slope form?

Mathematics
1 answer:
RSB [31]3 years ago
8 0

Answer:

Write in slope-intercept form,  y = m x + b

y=mx+b.

−

Step-by-step explanation:

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8х + 7y= -5<br> X= -3y - 7
GrogVix [38]

Answer:

x = 2

y = -3

Step-by-step explanation:

Step 1: Write systems of equation

8x + 7y = -5

x = -3y - 7

Step 2: Solve for <em>y</em>

  1. Substitute 2nd equation into 1st: 8(-3y - 7) + 7y = -5
  2. Distribute 8: -24y - 56 + 7y = -5
  3. Combine like terms: -17y - 56 = -5
  4. Add 56 to both sides: -17y = 51
  5. Divide both sides by -17: y = -3

Step 3: Solve for <em>x</em>

  1. Substitute <em>y</em> to find <em>x</em>: x = -3(-3) - 7
  2. Multiply: x = 9 - 7
  3. Subtract: x = 2

Step 4: Check

<em>Plug in x, y into an original equation to verify it's a solution.</em>

2 = -3(-3) - 7

2 = 9 - 7

2 = 2

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