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3 years ago

Can a triangle have sides of lengths 9,17,15? Show why or why not.

Mathematics

1 answer:

Elden [556K]3 years ago

6 0

Answer:

A triangle has 3 sides: a, b, c satisfying inequalities below:

=> a + b > c > |a - b|

=> b + c > a > |b - c|

=> c + a > b > |c - a|

9, 15, 17 satisfy the inequalities above (you can check it easily).

Hope this helps!

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KLMN is a parallelogram,

Aleonysh [2.5K]

Answer:

Ok soo.

Step-by-step explanation:

sum of two adjacent angles of parallelogram is 180

so angle K + angle L = 180

as AK bisects angle K and LA bisects angle L

so, angle AKL + angle ALK = 180 /2 = 90

in triangle AKL,

angle AKL + angle ALK+angle KAL = 180(sum of all angles in triangle = 180)

so, from above two equations,

angle KAL = 90

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2 years ago

There are seven days how many days are there in 16 weeks

Leya [2.2K]

There are 112 days in 16 weeks because all you have too do is take 16 and multiply it by 7 which gets you 112. Hope this helped.

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2 years ago

Read 2 more answers

Solve the x <br> 1/3x + 5> 10

kotykmax [81]

Answer:

The solution to the inequality is:

$\frac{1}{3}x+5>10\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>15\:\\ \:\mathrm{Interval\:Notation:}&\:\left(15,\:\infty \:\right)\end{bmatrix}$

The solution graph is also attached below.

Step-by-step explanation:

Given

We are given the expression

$\frac{1}{3}x+5>10$

To determine

Solve for x

Given the expression

$\frac{1}{3}x+5>10$

Subtract 5 from both sides

$\frac{1}{3}x+5-5>10-5$

Simplify

$\frac{1}{3}x>5$

Multiply both sides by 3

$3\cdot \frac{1}{3}x>5\cdot \:3$

Simplify

$x>15$

Thus, we conclude that:

$x>15$

Therefore, the solution to the inequality is:

$\frac{1}{3}x+5>10\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>15\:\\ \:\mathrm{Interval\:Notation:}&\:\left(15,\:\infty \:\right)\end{bmatrix}$

The solution graph is also attached below.