El mínimo común múltiplo de 20 14 y 17 es <u>1</u>.
17 es un número primo, y su únicos múltiplos son 17 y 1.
Quartile 1 is 211. quartile 2 is 226 , and quartile 3 is 265.5
Answer:
C=8k+24
Step-by-step explanation:
Answer:
1. x = 2, AC = 30, AB - 4
2. y = 4, AB = 34, BC = 34
Step-by-step explanation:
1. AB + BC = AC so 26 + (10 - 3x) = 14x +2 and then add 3x to both sides and subtract 2 from both sides to get x on one side and an integer on the other side which is 34 = 17x and then divide 17 from both sides to get x = 2 and then substitute x into the AC and AB equations to find the values its equal to.
2. The symbol in the given means that the two lengths are congruent which means they are equal to each other so you put the two equations equal to each other and solve for y. 9y -2 = 14 + 5y, so subtract 5y from both sides and add two to both sides to get 4y = 16 and then divide both sides by 4 to get y = 4 and then substitute in the answer to find the lengths of AB and BC.
