Substitute the values of the radius <span>(<span><span>r=3</span>),</span></span><span> the </span>height <span>(<span><span>h=11</span>),</span></span><span> and an approximation of </span>Pi <span>(<span>3.14)</span></span><span> into the </span>formula<span> to find the </span>volume<span> of the </span>cone<span>.
</span><span>V≈+<span>1/3</span>⋅3.14⋅<span>3^2</span>⋅11
</span><span>Simplify.
</span>Write 3.14<span> as a </span>fraction<span> with </span>denominator <span>1.</span><span>
</span><span>V≈+<span>1/3</span>⋅<span>3.14/1</span></span> <span>
</span>Combine <span>1/3</span><span> and </span><span>3.14/1</span><span> to get </span><span><span>3.14/3</span>.</span><span>
</span><span>V≈+<span>3.14/3</span></span><span>
</span>
Replace back in to larger expression<span>.
</span><span>V≈+<span>3.14/3</span>⋅<span>3^2</span>⋅11</span><span>
</span>
Divide 3.14<span> by </span>3<span> to get </span><span>1.04666667.
</span><span>V≈+1.04666667⋅<span>3^2</span>⋅11
</span>Raise 3<span> to the </span>power<span> of </span>2<span> to get </span><span>9.
</span><span>V≈+1.04666667⋅9⋅11
</span>Multiply 1.04666667<span> by </span>9<span> to get </span><span>9.42.
</span><span>V≈+9.42⋅11
</span>Multiply 9.42<span> by </span>11<span> to get </span><span>103.62.
</span><span>V≈+103.62
</span>Remove trailing zeros<span> from </span><span>103.62.
</span><span>V≈+103.62</span><span>f<span>t^3
Volume:
</span></span>V≈+103.62ft^3
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Answer:12
Step-by-step explanation:
