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Tema [17]
3 years ago
7

Shaz is cleaning under the kitchen sink. He found five 2-liter bottles of glass cleaner. None of the bottles is full. The bottle

s contain the following amounts.
Bottle 1 – 375 mL Bottle 2 – 150 mL Bottle 3 – 190 mL
Bottle 4 – 780 mL Bottle 5 – 630 mL
How many liters of glass cleaner do the five bottles contain in total?
If Shaz combines all of the glass cleaners into as few bottles as possible, how many bottles will he use?
Mathematics
2 answers:
Stels [109]3 years ago
6 0
Sbshehe fjshebd Shane
elixir [45]3 years ago
6 0

Step-by-step explanation:

375 + 150 + 190 + 780 + 630 = 2125 ml

For first question

2125 ml ÷ 10^3 = 2.125 liter

And by criss cross method 2 litter - > 1 bottle

2.125 liter - > x ( x is unknown)

X= 2.125 / 2 = 1.0625 bottles

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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
kow [346]

Answer:

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.

So 292 - 240 = 52 read below or at eight grade level, and that n = 292, \pi = \frac{52}{292} = 0.178

80% confidence level

So \alpha = 0.2, z is the value of Z that has a pvalue of 1 - \frac{0.2}{2} = 0.9, so Z = 1.28.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.149

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.207

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

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379.88 is the answer to this problem.
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Find an equation of the line passing through the following points (-8, 4) and (-5, -5)
oksian1 [2.3K]

Answer:

y= -3x-20

Step-by-step explanation:

°First find the gradient between the two points

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°Using the formula y= mx+c substitute the gradient into the equation. You'll get something like this: y=-3x+c

°Substitute the point (-8;4) in the above equation. You'll get something like this : 4=-3(-8) +c

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°Substitute c=-20 in the equation

Final answer is y= - 3x-20

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