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2 years ago

What is the range of possible sizes for side x? 8.8

Mathematics

1 answer:

eduard2 years ago

3 0

Answer:

The size of side x can range from 0.5 < x < 16.5.

The size of side x cannot take on values 0 and 16.5, but it ranges between those two values for side x to complete a triangle with those two other sides.

Step-by-step explanation:

Complete Question

What is the range of possible sizes for side x? One Side is 8.5 the other is 8.0.

Solution

With the logical assumption that the three sides are to form a triangle

Let the two sides given be y and z

And the angle between y and z be θ

The angle θ can take on values from 0° to 180° without reaching either values.

As θ approaches 0°, (x+z) becomes close to equaling y. (x + z) < y

It can never equal y, because θ can never be equal to 0°, if a triangle is to exist.

Hence, x > (z−y)

x > 8.5 - 8.0

x > 0.5

As θ approaches 180°, x approaches the sum y+z, θ can never equal 180° if a triangle is to exist, so x never equals (y+z).

Hence x < (y+z)

x < 8 + 8.5

x < 16.5

Hope this Helps!!!

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Algebra help - asymptotes

motikmotik

Find where the equation is undefined ( when the denominator is equal to 0.

Since they say x = 5, replace x in the equation see which ones equal o:

5-5 = 0

So we know the denominator has to be (x-5), this now narrows it down to the first two answers.

To find the horizontal asymptote, we need to look at an equation for a rational function: R(x) = ax^n / bx^m, where n is the degree of the numerator and m is the degree of the denominator.

In the equations given neither the numerator or denominators have an exponent ( neither are raised to a power)

so the degrees would be equal.

Since they are equal the horizontal asymptote is the y-intercept, which is given as -2.

This makes the first choice the correct answer.

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2 years ago

6. What is the literal coefficient? a. XYZ b. 2xyz C. XYZ d. 2x

yarga [219]

D is the right answer

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2 years ago

What is the simple interest on $2500 invested at an interest rate of 6% for 2 years?

Brrunno [24]

Answer:

The simple interest is $300.

Step-by-step explanation:

Find the Interest amount.

I: Interest ?

P: Principle Amount $2500

R: Rate 6% = .06

T: Time Period (in years) 2 Years

Convert into equation to find Simple Interest

I = Prt

I = (2500)(.06)(2)

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4 0

3 years ago

Read 2 more answers

A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime

Shalnov [3]

Answer:

We conclude that the true average percentage of organic matter in such soil is different from 3%.

Step-by-step explanation:

We are given that the values of the sample mean and sample standard deviation are 2.481 and 1.616, respectively.

Suppose we know the population distribution is normal, we have to test the hypothesis that does this data suggest that the true average percentage of organic matter in such soil is something other than 3%.

Let $\mu$ = true average percentage of organic matter in such soil

SO, Null Hypothesis, $H_0$ : $\mu$ = 3% {means that the true average percentage of organic matter in such soil is equal to 3%}

Alternate Hypothesis, $H_A$ : $\mu \neq$ 3% {means that the true average percentage of organic matter in such soil is different than 3%}

The test statistics that will be used here is One-sample t test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{{\frac{s}{\sqrt{n} } } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean amount of organic matter = 2.481%

s = sample standard deviation = 1.616%

n = sample of soil specimens = 30

So, test statistics = $\frac{0.02481-0.03}{{\frac{0.01616}{\sqrt{30} } } }$ ~ $t_2_9$

= -1.759

Now, P-value of the test statistics is given by;

P-value = P( $t_2_9$ > -1.759) = 0.046 or 4.6%

If the P-value of test statistics is more than the level of significance, then we will not reject our null hypothesis as it will not fall in the rejection region.

If the P-value of test statistics is less than the level of significance, then we will reject our null hypothesis as it will fall in the rejection region.

Now, here the P-value is 0.046 which is clearly smaller than the level of significance of 0.05 (for two-tailed test), so we will reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is different from 3%.

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Afina-wow [57]

Answer:

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3 years ago