Match each pair of equivalent fractions. 1 4. 1. 4/16 8 1 4/10 ni - 17 MI10 10 2 3. 3 12/18 5 4 4. 2. 16/20 6 NEXT QUESTION ASK
1 answer:
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Answer:
(i) 0.46, (ii)0.42, and (iii)0.143
Step-by-step explanation:
Let be the probability of hitting the target and
be the probability of missing the target by Laura.
Given that
As Laura either hit or miss the target, so .
Again, let be the probability of hitting the target and
be the probability of missing the target by Philip.
Here,
Similarly,
(i)The probability that the target is hit means that the target is not missed by both, either of one or both hit the target.
=1-(probability of missing the target by both)
=1- [from equation (2) and (4) ]
=
=
=0.46
(ii) The probability that the target is hit by exactly one shot means either of one hit the target.
=Hit by Laura and missed by Philip or hit by Philip and missed by Laura
[from equations (1),(4) and (3),(2)]
=0.42
(iii)Given that the target was hit by exactly one shot, so, the given probability is 0.42 [from (ii) part]
No, the probability that the target was hit by Philip = probability of hitting the target by Philip and missing the target by Laura
[from equations (3) and (2)]
=0.06
So, the probability of hitting the target by Philip
(approx)