The inerquartile range of 10 , 11 ,12 ,13 ,
2 answers:
Answer:
IQR = 2
Step-by-step explanation:
The first step is to find the median of the data set.
The median is the middle value of the data arranged in ascending order. If there is no middle value then it is the average of the values either side of the middle
10, 11, 12, 13
↑ middle
median = =
= 11.5
The interquartile range ( IQR) is the difference between the upper quartile Q₃ and the lower quartile Q₁
Q₃ is the middle of the data to the right of the median and Q₁ is the middle of the data to the left of the median.
12, 13
↑
Q₃ = =
= 12.5
10, 11
↑
Q₁ = =
= 10.5
Then
IQR = Q₃ - Q₁ = 12.5 - 10.5 = 2
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1. Divide your number into perfect square factors.
2. Take the square roots of your perfect square factors.
3. If your number doesn't factor perfectly, reduce your answer to simplest terms.
4. If needed, estimate. In some cases if you have memorized some of the square roots, you can estimate where the number would be.
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5. <span>Alternatively, reduce your number to its lowest common factors as your first step.</span><span> Finding perfect square factors isn't necessary if you can easily determine a number's prime factors (factors that are also prime numbers).
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