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tester [92]
3 years ago
10

The inerquartile range of 10 , 11 ,12 ,13 ,

Mathematics
2 answers:
Lorico [155]3 years ago
5 0

Answer:

IQR = 2

Step-by-step explanation:

The first step is to find the median of the data set.

The median is the middle value of the data arranged in ascending order. If there is no middle value then it is the average of the values either side of the middle

10,  11,  12,  13

         ↑ middle

median = \frac{11+12}{2} = \frac{23}{2} = 11.5

The interquartile range ( IQR) is the difference between the upper quartile Q₃ and the lower quartile Q₁

Q₃ is the middle of the data to the right of the median and Q₁ is the middle of the data to the left of the median.

12,  13

   ↑

Q₃ = \frac{12+13}{2} = \frac{25}{2} = 12.5

10, 11

   ↑

Q₁ = \frac{10+11}{2} = \frac{21}{2} = 10.5

Then

IQR = Q₃ - Q₁ = 12.5 - 10.5 = 2

Tatiana [17]3 years ago
4 0

Answer:

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Step-by-step explanation:

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Write f(x)=8x^2-4x+11 in vertex form
Vlad [161]

Answer:

f(x)=8(x-\frac{1}{4})^{2}+\frac{21}{2}

or

f(x)=8(x-0.25)^{2}+10.5

Step-by-step explanation:

we have

f(x)=8x^{2}-4x+11

This is a vertical parabola open upward (because the leading coefficient is positive)

The vertex is a minimum

Convert to vertex form

Factor the leading coefficient

f(x)=8(x^{2}-\frac{1}{2}x)+11

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)=8(x^{2}-\frac{1}{2}x+\frac{1}{16})+11-\frac{1}{2}

f(x)=8(x^{2}-\frac{1}{2}x+\frac{1}{16})+\frac{21}{2}

Rewrite as perfect squares

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or

f(x)=8(x-0.25)^{2}+10.5

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3 0
3 years ago
The area of a rectangular horse pasture is 268,500 square yards. The length of the pasture is 5 yards less than three times the
Setler79 [48]

Answer:  width = 300

<u>Step-by-step explanation:</u>

Area (A) = Length (L) x width (w)

Given: A = 268,500

           L = 3w - 5

           w = w

268,500 = (3w - 5) x (w)

268,500 = 3w² - 5w

            0 = 3w² - 5w - 268,500

            0 = (3w + 895) (w - 300)

   0 = 3w + 895        0 = w - 300

  -985/3 = w             300 = w

Since width cannot be negative, disregard w = -985/3

So the only valid answer is: w = 300

   

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3 years ago
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