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After a series of calculations using the interest formula:
The best and most correct answer among the choices provided by your question is the second choice or letter B "$0.18."
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Answer:
$17,277.07
Step-by-step explanation:
Present value of annuity is the present worth of cash flow that is to be received in the future, if future value is known, rate of interest is r and time is n then PV of annuity is
PV of annuity = ![\frac{P[1-(1+r)^{-n}]}{r}](https://tex.z-dn.net/?f=%5Cfrac%7BP%5B1-%281%2Br%29%5E%7B-n%7D%5D%7D%7Br%7D)
= ![\frac{3000[1-(1+0.10)^{-9}]}{0.10}](https://tex.z-dn.net/?f=%5Cfrac%7B3000%5B1-%281%2B0.10%29%5E%7B-9%7D%5D%7D%7B0.10%7D)
= ![\frac{3000[1-(1.10)^{-9}]}{0.10}](https://tex.z-dn.net/?f=%5Cfrac%7B3000%5B1-%281.10%29%5E%7B-9%7D%5D%7D%7B0.10%7D)
= ![\frac{3000[1-0.4240976184]}{0.10}](https://tex.z-dn.net/?f=%5Cfrac%7B3000%5B1-0.4240976184%5D%7D%7B0.10%7D)
= 
= 
= 17,277.071448 ≈ $17,277.07
Answer:
The difference in the sample proportions is not statistically significant at 0.05 significance level.
Step-by-step explanation:
Significance level is missing, it is α=0.05
Let p(public) be the proportion of alumni of the public university who attended at least one class reunion
p(private) be the proportion of alumni of the private university who attended at least one class reunion
Hypotheses are:
: p(public) = p(private)
: p(public) ≠ p(private)
The formula for the test statistic is given as:
z=
where
- p1 is the sample proportion of public university students who attended at least one class reunion (
)
- p2 is the sample proportion of private university students who attended at least one class reunion (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the alumni from public university (1311)
- n2 is the sample size of the students from private university (1038)
Then z=
=-0.207
Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.