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swat32
3 years ago
6

Doctor Jon sees 6 patients in 1 1⁄2 hours. Doctor Carol sees 10 patients in 2 hours. Which doctor sees more patients per hour?

Mathematics
1 answer:
ololo11 [35]3 years ago
6 0

Answer:

Carol      PLEASE GIVE BRAINLIEST

Step-by-step explanation:

Jon = 6 patients in 1.5 hours

6 ÷ 1.5 = 4 patients per hour


Carol = 10 patients in 2 hours

10 ÷ 2 = 5 patients an hour


Carol sees more patients per hour.

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What is the present value of ​$3,000 per year for 9 years discounted back to the present at 10 ​percent?
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$17,277.07

Step-by-step explanation:

Present value of annuity is the present worth of cash flow that is to be received in the future, if future value is known, rate of interest is r and time is n then PV of annuity is

PV of annuity = \frac{P[1-(1+r)^{-n}]}{r}

                      = \frac{3000[1-(1+0.10)^{-9}]}{0.10}

                      = \frac{3000[1-(1.10)^{-9}]}{0.10}

                      = \frac{3000[1-0.4240976184]}{0.10}

                      = \frac{3000(0.5759023816)}{0.10}

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3 0
3 years ago
A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa
Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is  α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion  

p(private) be the proportion of alumni of the private university who attended at least one class reunion  

Hypotheses are:

H_{0}: p(public) = p(private)

H_{a}: p(public) ≠ p(private)

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of  public university students who attended at least one class reunion  (\frac{808}{1311}=0.616)
  • p2 is the sample proportion of private university students who attended at least one class reunion  (\frac{647}{1038}=0.623)
  • p is the pool proportion of p1 and p2 (\frac{808+647}{1311+1038}=0.619)
  • n1 is the sample size of the alumni from public university (1311)
  • n2 is the sample size of the students from private university (1038)

Then z=\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}} =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.  

6 0
3 years ago
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