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3 years ago

Find the quotient of 2/3 and 4/5

Mathematics

2 answers:

Lorico [155]3 years ago

8 0

Answer:

$\frac{5}{6}$

Step-by-step explanation:

$\frac{2}{3} / \frac{4}{5}$

$\frac{2}{3} * \frac{5}{4}$

Simplified

$\frac{1}{3} * \frac{5}{2}$

$\frac{5}{6}$

Lelu [443]3 years ago

7 0

Answer:

Step-by-step explanation:

2/3 ÷ 4/5

= 2/3 ÷ 5/4 = 10/12

$\sqrt[10]{12}$ $\frac{-10}{2}$

= 2/3 ÷ 5/4 = 10/12 = 2

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A researcher examines 27 water samples for iron concentration. The mean iron concentration for the sample data is 0.802 cc/cubic

Delvig [45]

Answer:

90% confidence interval for the population mean iron concentration is [0.771 , 0.832].

Step-by-step explanation:

We are given that a researcher examines 27 water samples for iron concentration. The mean iron concentration for the sample data is 0.802 cc/cubic meter with a standard deviation of 0.093.

Firstly, the pivotal quantity for 90% confidence interval for the population mean iron concentration is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean iron concentration = 0.802 cc/cubic meter

s = sample standard deviation = 0.093

n = number of water samples = 27

$\mu$ = population mean

<em>Here for constructing 90% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.706 < $t_2_6$ < 1.706) = 0.90 {As the critical value of t at 26 degree of

freedom are -1.706 & 1.706 with P = 5%}

P(-1.706 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 1.706) = 0.90

P( $-1.706 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $1.706 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X -1.706 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +1.706 \times {\frac{s}{\sqrt{n} }$ ) = 0.90

<u>90% confidence interval for</u> $\mu$ = [ $\bar X -1.706 \times {\frac{s}{\sqrt{n} }$ , $\bar X +1.706 \times {\frac{s}{\sqrt{n} }$ ]

= [ $0.802 -1.706 \times {\frac{0.093}{\sqrt{27} }$ , $0.802 +1.706 \times {\frac{0.093}{\sqrt{27} }$ ]

= [0.771 , 0.832]

Therefore, 90% confidence interval for the population mean iron concentration is [0.771 , 0.832].

4 0

3 years ago

This table represents Mindy's check register. Her checking account had a balance of $647.60 on November 20.

Andreas93 [3]

Answer:

910.94

i got it right

4 0

3 years ago

Find the residual values, and use the graphing calculator tool to make a residual plot. A 4-column table with 5 rows. The first

Svetlanka [38]

The best answer from the options that proves that the residual plot shows that the line of best fit is appropriate for the data is: ( Statement 1 ) Yes, because the points have no clear pattern

X Given Predicted Residual value

1 3.5 4.06 -0.56

2 2.3 2.09 0.21

3 1.1 0.12 0.98

4 2.2 -1.85 4.05

5 -4.1 -3.82 -0.28

The residual value is calculated as follows using this formula: ( Given - predicted )

1) ( 3.5 - 4.06 ) = -0.56

2) ( 2.3 - 2.09 ) = 0.21

3) ( 1.1 - 0.12 ) = 0.98

4) (2.2 - (-1.85) = 4.05

5) ( -4.1 - (-3.82) = -0.28

Residual values are the difference between the given values and the predicted values in a given data set and the residual plot is used to represent these values .

attached below is the residual plot of the data set

hence we can conclude from the residual plot attached below that the line of best fit is appropriate for the data because the points have no clear pattern ( i.e. scattered )

learn more about residual plots : brainly.com/question/16821224