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3 years ago

Which expression is equal to f(x) · g(x)? f(x)=4x^2+3x and g(x)= -4x-6. PLEASE HELP

Mathematics

1 answer:

sveta [45]3 years ago

6 0

Answer:

-16x³ - 36x² - 18x

Step-by-step explanation:

So here we just need to multiply these two functions together

f(x)*g(x) = (4x² + 3x)(-4x - 6)

Our first step is to foil: (4x²)(-4x) + (4x²)(-6) + (3x)(-4x) + (3x)(-6)

Then we can simplify each term by multiplying : -16x³ - 24x² - 12x² - 18x

We can than combine any like terms: -16x³ - 36x² - 18x

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3 years ago

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Factor the expression completely.

Ksju [112]

Answer:

Step-by-step explanation:

-9.75 + 3.25x

3.25(-3 + x)

-3.25(3 - x)

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3 years ago

1+4x/6=3.5<br> What is x

bagirrra123 [75]

Answer:

x=3+3/4

Step-by-step explanation:

1+4x/6=3.5

We move all terms to the left:

1+4x/6-(3.5)=0

We add all the numbers together, and all the variables

4x/6-2.5=0

We multiply all the terms by the denominator

4x-(2.5)*6=0

We add all the numbers together, and all the variables

4x-15=0

We move all terms containing x to the left, all other terms to the right

4x=15

x=15/4

x=3+3/4

3 0

3 years ago

There are 8 pencils in a package. How many packages will be needed for 28 children if each child gets 4 pencils?

Verizon [17]

28*4=112
112/8=14 Packages

8 0

3 years ago

Which table shows a proportional relationship between x and y ?

insens350 [35]

Answer:

Table C

Step-by-step explanation:

Given

Table A to D

Required

Which shows a proportional relationship

To do this, we make use of:

$k = \frac{y}{x}$

Where k is the constant of proportionality.

In table (A)

x = 2, y = 4

$k = \frac{y}{x}$

$k = \frac{4}{2}$

$k = 2$

x = 4, y = 9

$k = \frac{y}{x}$

$k = \frac{9}{4}$

$k = 2.25$

Both values of k are different. Hence, no proportional relationship

In table (B)

x = 3, y = 4

$k = \frac{y}{x}$

$k = \frac{4}{3}$

$k = 1.33$

x = 9, y = 16

$k = \frac{y}{x}$

$k = \frac{16}{9}$

$k = 1.78$

Both values of k are different. Hence, no proportional relationship

In table (C):

x = 4, y = 12

$k = \frac{y}{x}$

$k = \frac{12}{4}$

$k = 3$

x = 5, y = 15

$k = \frac{y}{x}$

$k = \frac{15}{5}$

$k = 3$

x = 6, y = 18

$k = \frac{y}{x}$

$k = \frac{18}{6}$

$k = 3$

This shows a proportional relationship because all values of k are the same for this table

7 0

3 years ago