The number of solutions of a quadratic equation
ax^2+bx+c=0
Depends on its discriminant
/Delta=b^2-4ac
If /Delta>0 there are two distinct solutions
If /Delta=0 there are two coincident solutions
If /Delta<0 there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
The number of solutions of a quadratic equation
Depends on its discriminant
If there are two distinct solutions
If there are two coincident solutions
If there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
b^2-4ac=9+28t>0\iff t>-\dfrac[9][28]
Her gross Income was $7664
with gross Income just add up every dollar she earns NEVER WHAT SHE SPENDS
Eight times the quantity of a number and six.
8 (x+6)
Solving for y, we can start by expanding to get y-3=5x-20. Next, we can add 3 to both sides (to separate y), resulting in y=5x-17. To find the slope in the equation y=mx+b, you simply find what you multiply x by, which is 5 in this case. To find a perpendicular slope, you start by making the slope (5 in this case) negative. Next, we find the reciprocal of the number. Since -5 can be written as -5/1, the reciprocal and therefore perpendicular slope is -1/5