A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:
n!/((n-r)!r!)
In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.
5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5
5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10
5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10
5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5
Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.
Now we add together the combinations
1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.
The answer is 32.
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Note: There is also an equation for permutations which is:
n!/(n-r)!
Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.
We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.
I hope this helps! If you have any questions, let me know :)
Answer:
yards because it can't be squared if its a circle
Step-by-step explanation:
Answer:
1-9 the answer is -8of the circle
Step-by-step explanation:
Area of a rectangular lawn = l×b
255=15×x
Hence the breadth is 17 m
Hence perimeter =2(l+b)=2(15+17)=64
Answer:
3a:20d+35
3b:35u+49q+56
4a:15+20t
4b:96k+120t+84
5a:24t+108m+60
5b:56q+28b+35
6a:14q+10w+24
6b:54v+99+27t
7a:16g+24+24c
7b:30a+55+50d
(i think thats what they are but the picture is small so its kind of hard to see)
Step-by-step explanation:
(since theres 10 total ill just give an example on how i solved 5a)
5(4d+7)
simplify into: (5•4d)+(5•7)
multiply: (20d)+(35)
since you do not know what d is, you cannot add them
remove parentheses once done:20d+35
(you don't need parentheses since multiplication come before addition but its easier to just use them)
<h2>Hope this helps</h2>
