Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
4+4+6+6=12+8=20
hope this helps
62.5% of 56 is 35
Divide 35 and 56:
Convert the decimal to a percentage:
Exponential form has the little number exponent at the top but sadly I can only represent that here with a ^ meaning to the power of.
5y^4*x^3
So distance = rate × time. You would do 3/4 × 5.5, which would get you 4.125.