<span>12.3
Volume function: v(x) = ((18-x)(x-1)^2)/(4pi)
Since the perimeter of the piece of sheet metal is 36, the height of the tube created will be 36/2 - x = 18-x.
The volume of the tube will be the area of the cross section multiplied by the height. The area of the cross section will be pi r^2 and r will be (x-1)/(2pi). So the volume of the tube is
v(x) = (18-x)pi((x-1)/(2pi))^2
v(x) = (18-x)pi((x-1)^2/(4pi^2))
v(x) = ((18-x)(x-1)^2)/(4pi)
The maximum volume will happen when the value of the first derivative is zero. So calculate the first derivative:
v'(x) = (x-1)(3x - 37) / (4pi)
Convert to quadratic equation.
(3x^2 - 40x + 37)/(4pi) = 0
3/(4pi)x^2 - (10/pi)x + 37/(4pi) = 0
Now calculate the roots using the quadratic formula with a = 3/(4pi), b = -10/pi, and c = 37/(4pi)
The roots occur at x = 1 and x = 12 1/3. There are the points where the slope of the volume equation is zero. The root of 1 happens just as the volume of the tube is 0. So the root of 12 1/3 is the value you want where the volume of the tube is maximized. So the answer to the nearest tenth is 12.3</span>
200 m to 4 hours
200/4
50m/1hour
144 cm3 is what i came up with!
Answer:
Step-by-step explanation:
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Answer:
The cost of producing the article is -3500 (Negative cost)
Step-by-step explanation:
The given parameters are
The ratio of the profit to material cost to production labor = 5:7:13
The amount of the material cost = 840 + Labor cost
Let the total cost = X
Therefore, we have;
The fraction of the total cost that is material cost = 7/(5 + 7 + 13) = 7/25
Therefore, the material cost = 7/25 × X
The fraction of the total cost that is labor cost = 13/(5 + 7 + 13) = 13/25
Therefore, the labor cost = 13/25 × X
However, the amount of the material cost = 840 + Labor cost, which gives;
7/25 × X = 13/25 × X + 840
7/25 × X - 13/25 × X = 840
-6/25 × X= 840
X = 840/(-6/25) = 840×(-25/6) = -3500
The cost of producing the article = -3500.
