It's annuity problem
To solve your question use the formula of the present value of annuity ordinary which is
Pv=pmt [(1-(1+r)^(-n))÷r]
Pv present value?
PMT yearly payments 18000
R interest rate 0.09
N time 20 years
So
Pv=18,000×((1−(1+0.09)^(−20))÷(0.09))
pv=164,313.82
9. 5y
10.10x^2-1
not done
Yes she is correct..
the reason why is because if she gives her horse 2 apples a day for 10 days, she will have spent 20 apples.
and so to get the number of apples she has remaining after 10 days, just subtract 20 from 24:
24-20 = 4
and you get four. That means that after 10 days she will indeed have 4 apples left
Answer:
Step-by-step explanation:
Assuming a normal distribution for the amount spent by Canadian households for high-speed broadband access, the formula for normal distribution is expressed as
z = (x - u)/s
Where
x = amount spent by the Canadian households.
u = mean amount spent monthly.
s = standard deviation
From the information given,
u = $80.63 CDN
s = $27.32 CDN
We want to find the probability that the average amount will exceed $85. It is expressed as
P(x greater than 85) = 1 - P(x lesser than or equal to 85)
For x = 85
z = (85 - 80)/27.32 = 0.18
Looking at the normal distribution table, the corresponding z score is 0.57142
P(x greater than 85) = 1 - 0.57142 = 0.43
Answer:
-2
Step-by-step explanation:
-15x times -2 equals 30
