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arsen [322]
3 years ago
9

Describe how to find the measurement of angle L using the measurement of angle C.

Mathematics
2 answers:
Leona [35]3 years ago
7 0

Answer:

Since we can see that angle L and angle C are supplementary angles, we have the following equation:

∠C + ∠L = 180°

Therefore to find the measurement of angle C, we need to subjact the measurement of angle C from 180°:

∠L = 180° - ∠C

Paha777 [63]3 years ago
7 0

Answer:Angle L and angle C are supplementary angles. The sum of supplementary angles is 180°. So, I can find the measurement of angle L by subtracting the measurement of angle C from 180°.

Step-by-step explanation:

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GarryVolchara [31]

Answer:

The missing statement is ∠ACB ≅ ∠ECD

Step-by-step explanation:

Given two lines segment AC and BD bisect each other at C.

We have to prove that ΔACB ≅ ΔECD

In triangle ACB and ECD

AC=CE    (Given)

BC=CD   (Given)

Now to prove above two triangles congruent we need one more side or angle

so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles

hence, the missing statement is ∠ACB ≅ ∠ECD


9 0
3 years ago
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valentinak56 [21]

Answer:

at aircraft(at z) sported by

6 0
2 years ago
Help! will give points for brainliest
Misha Larkins [42]

Answer:

27

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6 0
3 years ago
How to turn this equation: <br> y= -1.02(x-3)^2+9.25<br> into factored form
MatroZZZ [7]

Answer:

y=(102x-306-5\sqrt{3774})(102x-306+5\sqrt{3774})

Step-by-step explanation:

You first equate it to zero to get:

-1.02(x-3)^2+9.25=0

Then solve using square root method

-1.02(x-3)^2=-9.25

(x-3)^2=\frac{-9.25}{-1.02}

(x-3)^2=\frac{925}{102}

x=3\pm\sqrt{\frac{925}{102}}

Or

x=3\pm{\frac{5\sqrt{3774}}{102}}

x={\frac{306\pm5\sqrt{3774}}{102}}

Now work it backwards

102x-(306\pm5\sqrt{3774})=0

(102x-306-5\sqrt{3774})(102x-306+5\sqrt{3774})=0

Hence the factored form is:

y=(102x-306-5\sqrt{3774})(102x-306+5\sqrt{3774})

8 0
3 years ago
What are the correct answers?
Delvig [45]
1. y= -x - 15
2. y= -4x + 1/2
3. y= 2x + 1
4. y= 2/3x + 3
5. y= -1/2x - 4
6. y= -3x + 13

Glad I could help
8 0
3 years ago
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