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3 years ago

4. Find the value of k, if x = 2, y=1 is a solution of the equation 2x + 3y=k.

Mathematics

1 answer:

icang [17]3 years ago

3 0

Answer:

k=7

Step-by-step explanation:

first, plug in the given values

2x+3y=k --> 2(2)+3(1)=k

-->4+3=k

-->7=k

k=7

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Read 2 more answers

The class scores of a history test have a normal distribution with a mean Mu = 79 and a standard deviation Sigma = 7. If Opal’s

e-lub [12.9K]

Using the normal distribution, we got that expression for the z-score of her test score is

$z= \frac{72-29}{7} \\\\z=-7/7\\\\z=-1$

<h3>What is Normal Probability Distribution?</h3>

it's a type of probability distribution which is symmetric about the mean, it gives data near the mean are more frequent than data far from the mean.

Given that mean = $\mu=79$

and standard deviation = $\sigma = 7$

X=73

we know that formula of z-score is

$z=\frac{X-\mu}{\sigma}$

Hence Z-score can be calculated as

$z= \frac{72-29}{7} \\\\z=-7/7\\\\z=-1$

Using the normal distribution, we got that expression for the z-score of her test score is

$z= \frac{72-29}{7} \\\\z=-7/7\\\\z=-1$

To learn more about the normal distribution visit : brainly.com/question/24663213

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2 years ago

4. Find the value of k, if x = 2, y=1 is a solution of the equation 2x + 3y=k.​

4. Find the value of k, if x = 2, y=1 is a solution of the equation 2x + 3y=k.