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vodomira [7]
3 years ago
12

Which system of equations can be used to find the roots of the equation 12 x cubed minus 5 x = 2 x squared + x + 6? StartLayout

Enlarged left-brace 1st Row y = 12 x cubed minus 5 x 2nd row y = 2 x squared + x + 6 EndLayout StartLayout Enlarged left-brace 1st Row y = 12 x cubed minus 5 x + 6 2nd row y = 2 x squared + x EndLayout StartLayout Enlarged left-brace 1st Row y = 12 x cubed + 2 x squared minus 4 x 2nd row y = 6 EndLayout StartLayout Enlarged left-brace 1st Row y = 12 x cubed + 2 x squared minus 4 x + 6 2nd row y = 0 EndLayout
Mathematics
1 answer:
OverLord2011 [107]3 years ago
7 0

Answer:

A

Step-by-step explanation:

12x³-5x=2x²+x+6

y=12x³-5x

y=2x²+x+6

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If ur reading this right now plz help me whenever I ask a question, this random account under different names keeps sending me r
denis23 [38]

Answer:

C

Step-by-step explanation:

3/4 of 1000 is 750 and 1/5 of 750 is 150 so your answer is C

5 0
3 years ago
A 6m ladder leans against a wall. The bottom of the ladder is 1.3m from the wall at time =0sec and slides away from the wall at
icang [17]

Answer:

- 0.100

Step-by-step explanation:

Length of the ladder,  H = 6 m

Distance at the bottom from the wall, B = 1.3 m

Let the distance of top of the ladder from the bottom at the wall is P

Thus,

from  Pythagoras theorem,

B² + P² = H²    .

or

B² + P² = 6²          ..............(1)      [Since length of the ladder remains constant]

at B = 1.3 m

1.3² + P² = 6²

or

P² = 36 - 1.69

or

P² = 34.31

or

P = 5.857

Now,

differentiating (1)

2B(\frac{dB}{dt})+2P(\frac{dP}{dt})=0

at t = 2 seconds

change in B = 0.3 × 2= 0.6 ft

Thus,

at 2 seconds

B = 1.3 + 0.6 = 1.9 m

therefore,

1.9² + P² = 6²

or

P = 5.69 m

on substituting the given values,

2(1.9)(0.3) + 2(5.69) × (\frac{dP}{dt}) = 0

or

1.14 + 11.38 × (\frac{dP}{dt}) = 0

or

11.38 × (\frac{dP}{dt}) = - 1.14

or

(\frac{dP}{dt}) = - 0.100

here, negative sign means that the velocity is in downward direction as upward is positive

5 0
3 years ago
Boris can type 56 words in 8 minutes. What is his rate in words per minute?
amid [387]
7 words per minute! :) Hope I helped!!

7 0
3 years ago
Read 2 more answers
Which expressions are equivalent to 2(b+3c)?
Rina8888 [55]

Answer:

B. (b+3c)+(b+3c)

C. 2(b)+2(3c)

Step-by-step explanation:

we have

2(b+3c)

Distribute the number 2

2(b+3c)=2b+2(3c)=2b+6c

Verify each case

case A) 3(b+2c)

distribute the number 3

3(b+2c)=3b+3(2c)=3b+6c

3b+6c \neq 2b+6c

therefore

Choice A is not equivalent to the given expression

case B) (b+3c)+(b+3c)

Combine like terms

b+3c)+(b+3c)=(b+b)=(3c+3c)=2b+6c

2b+6c= 2b+6c

therefore

Choice B is equivalent to the given expression

case C) 2(b)+2(3c)

Multiply both terns by 2

2(b)+2(3c)=2b+6c

2b+6c= 2b+6c

therefore

Choice C is equivalent to the given expression

6 0
3 years ago
Read 2 more answers
24 less than 4 times a number is 60. what is the number?
kondaur [170]
Hey there! :D

Make an algebraic expression. 

Let the 'number' equal x. 

4x-24= 60

Add 24 on both sides. 

4x= 84

Divide both sides by 4. 

x=21

The number is 21. 

I hope this helps!
~kaikers 
8 0
3 years ago
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