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wariber [46]
3 years ago
5

Can someone help me out with this?​

Mathematics
1 answer:
Phoenix [80]3 years ago
5 0

Answer:

i think it is the 3rd one though i am not sure sorry

Step-by-step explanation:

if it is not the 3rd one then it is the 1st one

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Two of the 240 passengers are chosen at random. Find the probability that
hjlf

Step-by-step explanation:

there are in total 240 passengers.

out of these 240, there are 150+30=180 passengers that are in holiday.

and 240-180 = 60 passengers are not.

if we pick one passenger then the probability is 180/240 = 3/4 = 0.75 that he/she is on holiday.

remember : desired "events" over total "events".

i)

now we pick 2 passengers.

the probabilty for the first one to be on holiday is again

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and to pick one out of that pool to be on holiday is then

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please note that after the first pull we need to update the numbers for the remaining pool depending on the result of the first pull.

the total remaining is in both cases 239. but either the remaining people on holiday go down to 179 (and not in holiday stays 60), or the remaining people not on holiday go down to 59 (and on holiday stays 180).

so, the first one is on holiday, and the second one is not :

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so, the probability for exactly one of the picked passengers to be on holiday is

2×0.188284519... = 0.376569038... ≈ 0.3766

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