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Vlada [557]
3 years ago
15

How many groups of 15 minutes are there in 1 3/4 hours​

Mathematics
1 answer:
gulaghasi [49]3 years ago
8 0

Answer:

7 groups

Step-by-step explanation:

1 hour = 60 minutes

3/4 of an hour = 3/4(60) = 45 minutes

therefore, 1 3/4 hours is 105 minutes

105 divided by 15 is 7

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Can someone help pls.
kap26 [50]

<em>My goodness, this is rather confusing in the way it is worded. Nevertheless, I will attempt to do what I can. Just please keep in mind that this is my own interpretation of the problem, and therefore could be... incorrect.</em>

<em>I think, to start out, we could set up the problem like so</em>

<em>15 + t ≥ 26</em>

<em>because t is not a set number. </em>

<em>Then all that is needed is to subtract 15 from both sides, and the equation becomes</em>

<em>t ≥ 11</em>

<em>So the resulting answer is t ≥ 11.</em>

<em />

<em>I hope that my interpretation helps.</em>

<em>-Toremi</em>

<em />

8 0
2 years ago
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Can anyone explain step by step how to get this answer?<br><br><br> Will mark branliest!!
Y_Kistochka [10]

Answer:

Step-by-step explanation:

28°

4 0
2 years ago
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0.4= Blankx10 please answer quick
Marta_Voda [28]

Answer:

1, 0.4

2, 0.004

3, 0.04

Step-by-step explanation:

hope this helps.      :)

6 0
3 years ago
1. Determine if the set of ordered pairs is a relation or a function.
kykrilka [37]

Answer:

This is just a relation.

Step-by-step explanation:

It is easy to see if a set of ordered pairs is a relation or a relation that is a function.

If all the points are distinct, then you just have to look at the x-coordinates.

If all the x-coordinates are different, then it is a function. Otherwise, it is a just a relation.

So this cannot be a function because there is at least two different points that have x=0.

5 0
3 years ago
What is f(g(x)) for x &gt; 5?
mel-nik [20]

Answer:

\large\boxed{B.\ 4x^2-41x+105}

Step-by-step explanation:

f(x)=4x-\sqrt{x}\\\\g(x)=(x-5)^2\\\\f(g(x))\to\text{put}\ x=(x-5)^2\ \text{to}\ f(x):\\\\f(g(x))=f\bigg((x-5)^2\bigg)=4(x-5)^2-\sqrt{(x-5)^2}\\\\\text{use}\\(a-b)^2=a^2-2ab+b^2\\\sqrt{x^2}=|x|\\\\f(g(x)=4(x^2-2(x)(5)+5^2)-|x-5|\\\\x>5,\ \text{therefore}\ x-5>0\to|x-5|=x-5\\\\f(g(x))=4(x^2-10x+25)-(x-5)\\\\\text{use the distributive property:}\ a(b+c)=ab+ac\\\\f(g(x))=(4)(x^2)+(4)(-10x)+(4)(25)-x-(-5)\\\\f(g(x))=4x^2-40x+100-x+5\\\\\text{combine like terms}\\\\f(g(x))=4x^2+(-40x-x)+(100+5)\\\\f(g(x))=4x^2-41x+105

6 0
3 years ago
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