Answer:
<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that, 
So, the <u>speed of Pratap with the current</u> will be:
miles/hour
and the <u>speed of Pratap against the current</u> will be:
miles/hour.
Suppose, the rate of Pratap in still water is
and the rate of current is
.
So, the equations will be........

Adding equation (1) and (2) , we will get......

Now, plugging this
into equation (1), we will get.....

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.
Actually I didn't see the (-5, -27), the answer would be -2.
She spends 14 days in Texas
Answer:

Step-by-step explanation:
8^2+5^2=c^2
64+25=c^2
89=c^2
c=
<-- this is the length of the rectangle at the bottom
2^2+(
)^2=c^2
4+89=c^2
c=
<-- length of dotted line (diagonal)
Answer:
Step-by-step explanation:
Take 20( cosine of 75 degrees)
the answer is 5 ft