Before going into the details of the problem, let us first write down the most important information required for solving this problem.
1 ft = 12 inches
The distance that was crawled by Jack = 4 ft
= (4 * 12) inches
= 48 inches
The distance crawled by Christine = 3/4 of the distance crawled by Jack
= (3/4) * 48 inches
= 3 * 12 inches
= 36 inches
Then
The total distance crawled by the two children's = (48 + 36) inches
= 84 inches
So Jack and Christine together crawled a distance of 84 inches.
It can't be simplified since 29 is a prime number EDIT: it cant be simplified into whole numbers lol
Answer:
Step-by-step explanation:
Given
2 number die
Required
P(Sum = 4)
The sample space of 2 die is:
The pairs that adds up to 4 are:
So, the probability is:
