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2 years ago

Divide 4^2/4^6 a. 4^-3 b. 4^3 c. 4^-4 d. 4^4

1 answer:

8 0

When dividing indices with the same base, the rule is to subtract the index of the denominator from the index of the numerator, and to keep the base the same.

In this case, the index of our denominator is 6, and the index of the numerator is 2.

2-6 = -4

The answer is $4^{-4}$ .

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Csc A - sin A = <br><br> A. (cos^2A) / (sinA)<br> B. (1 - sinA) / (sinA) <br> C. (1 - sinA) / (cosA)

julsineya [31]

Answer:

A) $\frac{cos^2A}{sinA}$

Step-by-step explanation:

$cscA-sinA\\\\\frac{1}{sinA}-sinA\\ \\\frac{1}{sinA}-\frac{sin^2A}{sinA}\\ \\ \frac{1-sin^2A}{sinA}\\ \\\frac{cos^2A}{sinA}$

4 0

2 years ago

Read 2 more answers

Which value for k makes the equation 42 ÷ k = 14 true? Select all that apply. A. 588 B. 62 C. 1452 D. 3 E. 23

Alexus [3.1K]

Answer:

Step-by-step explanation:

What divided by 42 equals 14? In other words, you have an unknown number (X), and then if you divide that X by 42 you get 14. Then what is that X? The equation to calculate what divided by 42 equals 14 is as follows: X/42 = 14 Where X is the answer. When we solve the equation by multiplying each side by 42, you get get:

X = 588

3 0

2 years ago

A car's position is given by s(t) = {3 – 5t? + 7t hundreds of meters with t in minutes.

Nadya [2.5K]

Answer:

A) (1 s, 2.3 s)

B) (-4 m/s², 3.8 m/s²)

Step-by-step explanation:

The car's position which is the distance is given by the equation;

s(t) = t³ - 5t² + 7t

A) Velocity is the first derivative of the distance. Thus;

v(t) = ds/dt = 3t² - 10t + 7

At v = 0, we have;

3t² - 10t + 7 = 0

Using quadratic formula, we have;

t = 1 and t = 2.3

Thus, time at velocity of 0 is t = (1 s, 2.3 s)

B) acceleration is the derivative of the velocity. Thus;

a(t) = dV/dt = 6t - 10

At velocity of 0, we got t = 1 and t = 2.3

Thus;

a(1) = 6(1) - 10 = -4 m/s²

a(2.3) = 6(2.3) - 10 = 3.8 m/s

Thus, a(t) at v = 0 gives; (-4 m/s², 3.8 m/s²)

8 0

2 years ago

Please help me answer this!!!!

garik1379 [7]

<h3><u>Answer</u><u>:</u></h3>

$7 \frac{1}{2}$

<h3><u>Explan</u><u>ation</u><u>:</u></h3>

First, convert any mixed numbers to fractions. An easy way to convert:

$4 \frac{1}{2} = 4 \times 2 + 1$

$\frac{9}{2} \div \frac{3}{5}$

Then, apply the fractions formula for division.

$\frac{9 \times5 }{2 \times 3} = \frac{45}{6}$

Then, simplify.

$\frac{45}{6} = 7 \frac{1}{2}$

5 0

2 years ago

On average, Jaimie can bike five times as fast as he can run. To travel 25 km, he needs 2 h more if he is running than if he is

monitta

Answer: Running speed is 10k/h

Biking speed is 50k/h

Step-by-step explanation:

My procedure may be unconventional, but it works:

Compute the time it takes, then translate to speed. 25k at biking speed takes 2 hours less than at running speed which is 1/5 bike speed.

Distance/speed = time 25/x=25/(5x-2) cross multiply divisors

25(5x-2) = 25x ==> 125x -50 =25x ==> 100x = 50

x = 0.5 hours at biking speed 25k/0.5h = 50k/h

Running speed = 50/5 10k/h

Proof: 25k/ 10k/h = 2.5 hours

25k /50k/h = 0.5 hours

2.5 h - .5 h = 2 hours, the difference stated in the question.

6 0

2 years ago