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3 years ago

HELP! 15 POINTS AND BRAINLIEST!

Mathematics

2 answers:

11Alexandr11 [23.1K]3 years ago

7 0

Answer:

8x squared 3

Step-by-step explanation:

hope this helps hope you get it right answer is d

Artyom0805 [142]3 years ago

6 0

Answer:

Step-by-step explanation:

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Point B is the center of a circle, and AC is a diameter of the circle. Point D is a point on the circle different from A and C.

seropon [69]

BA and BD are radii of the circle, so triangle ABD is isosceles. Then angles BDA and BAD are congruent, and the remaining (central) angle ABD has measure

$m\angle ABD=(180-2\cdot20)^\circ=140^\circ$

Angles ABD and CBD are supplementary, so

$m\angle CBD=(180-140)^\circ=40^\circ$

and the answer is E.

8 0

3 years ago

Determine the first four terms of the sequence in which the nth term is

Licemer1 [7]

Answer:

The correct answer option is: $\frac{1}{3} ,\frac{1}{4} ,\frac{1}{5} ,\frac{1}{6}$ .

Step-by-step explanation:

We know that the $nth$ term $a_n$ for an arithmetic sequence is given by:

$a_n=\frac{(n+1)!}{(n+2)!}$

where $n$ is the number of the position of the term.

We are supposed to find the first four terms of the sequence so we will substitute the values of $n$ from 1 to 4 in the given formula to get:

1st term:

$a_1=\frac{(1+1)!}{(1+2)!}=\frac{1}{3}$

2nd term:

$a_2=\frac{(2+1)!}{(2+2)!}=\frac{1}{4}$

3rd term:

$a_3=\frac{(3+1)!}{(3+2)!}=\frac{1}{5}$

4th term:

$a_4=\frac{(4+1)!}{(4+2)!}=\frac{1}{6}$

8 0

3 years ago

•The sentence 3+(5+2)=(5+2)+3 shows property?

laila [671]

Associative property is your answer

The Associative property states that no matter which group is parenthesized, the answer will still be the same.

hope this helps

4 0

3 years ago

Last week, Eric borrowed $62.90 from his parents. This week, Eric’s brother, John, borrowed $55.50 from their parents.

Hitman42 [59]

Answer:

Step-by-step explanation:

A because 62.90 is more than 55.50 so eric owes ore to his parents

4 0

2 years ago

the set $s = \$ contains the first $50$ positive integers. after the multiples of 2 and the multiples of 3 are removed, how many

Sophie [7]

Clearly, |S| = 50.

Count the multiples of 2 between 1 and 50:

⌊50/2⌋ = ⌊25⌋ = 25

(where ⌊x⌋ denotes the "floor of x", or the largest integer that is smaller than or equal to x; in other words, round down to the nearest integer)

Count the multiples of 3 between 1 and 50:

⌊50/3⌋ ≈ ⌊16.667⌋ = 16

Since LCM(2, 3) = 6, the sets of multiples of 2 and multiples of 3 have some overlap. Count the multiples of 6 between 1 and 50:

⌊50/6⌋ ≈ ⌊8.333⌋ = 8

Then by the inclusion/exclusion principle, we remove from S

25 + 16 - 8 = 33

elements, so that the new set S contains 50 - 33 = 17 elements.

5 0

2 years ago