Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
Answer: x=90
Step-by-step explanation: 11 x 7.5 =90
Answer:
Tickets sold:
VIP 
$17 tickets 
$21 tickets 
Step-by-step explanation:
Let x be the number of VIP tickets.
If ten times as many $17 tickets were sold as VIP tickets, then the number of $17 tickets is
If the number of $17 tickets sold was 57 more than the sum of the number of $21 tickets and VIP tickets, then
and the number y of $21 tickets is 
Amounts earned:
VIP tickets 
$17 tickets 
$21 tickets 
Total 
The sales of all three kinds of tickets would total $51,471, so

Tickets sold:
VIP 
$17 tickets 
$21 tickets 
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