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3 years ago

7

Farmer Bob's daughter wanted to put carpet in her goats pen. The pen is 12 feet wide and 12 feet long. How many square feet of c

arpet does she need for the pen

1 answer:

schepotkina [342]3 years ago

6 0

Answer:

She would need 144 square feet of carpet.

Step-by-step explanation:

Since the pen is 12 feet by 12 feet you would multiply 12 by 12 for your answer of 144 square feet.

You might be interested in

Marianna [84]

The expression into a single logarithm is $log[(x)^{10}][(2)^{30}]$

Step-by-step explanation:

Let us revise some logarithmic rules

$log(a)^{n}=nlog(a)$
$log(ab)=log(a)+log(b)$
$nlog(a)+mlog(b)=log[(a)^{n}][(b)^{m}]$

∵ 10 log(x) + 5 log(64)

- At first re-write 10 log(x)

∴ 10 log(x) = $log(x)^{10}$

- Then re-write 5 log(64)

∴ 5 log(64) = $log(64)^{5}$

∴ 10 log(x) + 5 log(64) = $log(x)^{10}$ + $log(64)^{5}$

- Use the 3rd rule above to make it single logarithm

∵ $log(x)^{10}$ + $log(64)^{5}$ = $log[(x)^{10}][(64)^{5}]$

∴ 10 log(x) + 5 log(64) = $log[(x)^{10}][(64)^{5}]$

∵ 64 = 2 × 2 × 2 × 2 × 2 × 2

∴ We can write 64 as $2^{6}$

∴ $(64)^{5}=(2^{6})^{5}$

- Multiply the two powers of 2

∴ $(64)^{5}=(2)^{30}$

∴ 10 log(x) + 5 log(64) = $log[(x)^{10}][(2)^{30}]$

The expression into a single logarithm is $log[(x)^{10}][(2)^{30}]$

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

6 0

3 years ago

Which one of these four sets of side lengths will form a right triangle?

zhuklara [117]

To be a right triangle, the hypotenuse^2 must equal side1^2 + side2^2

Only set 2 meets these conditions

8, sq root (29), sq root (35) then squaring these:

64, 29, 35

64 = 29 + 35

4 0

4 years ago

Read 2 more answers

What is the image of the point (5,-4) after a rotation of 90° counterclockwise about the origin?

Debora [2.8K]

Answer:

(4,5)

Step-by-step explanation:

Rotating a <em>point </em>by 90 degrees <em>counterclockwise</em> would make the y become x and switch it's negative/positive value, and make x the y.

Ex: (x,y) would become (-y,x)

4 0

3 years ago

Find the 5th term of the sequence in which t1 = 8 and tn-1 = t= -3tn-1

il63 [147K]

I think you mean to say that the sequence is given recursively by

$\begin{cases}t_1=8\\t_n=-3t_{n-1}\end{cases}$

From this you can find a general pattern for the $n$ th term, but since we're only interested in determining $t_5$ , we can stop once we arrive at that. We have

$t_2=-3t_1$
$t_3=-3t_2=(-3)^2t_1$
$t_4=-3t_3=(-3)^3t_1$
$t_5=-3t_4=(-3)^4t_1$

$\implies t_5=8(-3)^4=8(81)=648$

7 0

3 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago