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arlik [135]
3 years ago
10

How many two-digit positive integers can be formed the digits 1,5,6, and 8 if no digit is repeated?

Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

12

Step-by-step explanation:

There are 4 different digits to choose from. Since we want 2-digit number, we will see what digits can we put in place of 1st digit and what digit can we place in place of 2nd digit.

Hence, <u><em>how many digits (from 1,5,6 and 8) can be placed in the 1st digit of the number we want?</em></u>

Any one of the four digits (1,5,6, or 8).

Now, <em><u>How many digits (from 1,5,6 and 8) can be placed as the 2nd digit of the number we want?</u></em>

Any one of the THREE digits (since repetition is not allowed, we disregard the initial digit).

Thus the number of two-digit positive integers is 4 * 3 = 12

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