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Serga [27]
3 years ago
11

If the garage is open Monday to Saturday, determine the probability that the garage gets any demand for windscreen on Monday.

Mathematics
1 answer:
OLga [1]3 years ago
3 0

Answer: 1/6

Step-by-step explanation:

Since the garage is opened from Monday to Saturday, there'll be six possible outcomes which will be:

Monday, Tuesday, Wednesday, Thursday, Friday and Saturday.

Therefore, the probability that the garage gets any demand for windscreen on Monday will be:

= 1/6

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for x = 3, 5*3 - 2 = 13 > 7
for x = 4, 5*4 - 2 = 18 > 7
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Please help me? step by step:) ty
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multiply the dimensions of the lighter square

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*don't add because it's area; just multiply

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Find the arc length of the semicircle. Either enter an exact answer in terms of π or use 3.14 for π and enter your answer as a d
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

The formula for the length of an arc is s = rФ.

Thus, the arc length of a semicircle is S = rФ/2.

Here the radius is 5 (half the diameter), and so in this case the arc length is

S = (5 units)π/2, or S = (5/2)(3.14) units, or approximately S = 7.85 units

6 0
3 years ago
solo el 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal. Si
prisoha [69]

Usando la distribución binomial, hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

<h3>¿Qué es la distribución binomial?</h3>

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

Los parámetros son:

  • n es el número de ensayos.
  • p es la probabilidad de éxito en un ensayo
  • x es el número de éxitos

En este problema, hay que:

  • 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal, o sea p = 0.2.
  • Llegan 10 empleados, o sea, n = 10.

La probabilidad de que el guardia de seguridad encuentre al menos uno en la base militar restringida es dada por:

P(X \geq 1) = 1 - P(X = 0)

En que:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074

Por eso:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1074 = 0.8926

Hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

Puede-se aprender más a cerca de la distribución binomial en brainly.com/question/25132113

3 0
2 years ago
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