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Lynna [10]
3 years ago
13

Which is equivalent to 8.03 X 10^-8

Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

0.00000008

Step-by-step explanation:

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What is the value of 0.52 +<br> 3<br> 5
Mrrafil [7]

Answer: 35.52

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Step by step what is 3 (x+2)+5x
lesya692 [45]

Answer:

8x+6

Step-by-step explanation:

To simplify it, the first thing you want to do is distribute the three.


So

3(x+2) = 3x+6,

So we can then add the 5x to it.

3x+6+5x

Then, Combine Like Terms

8x+6

6 0
3 years ago
Please show how you got the answer, thanks.
FrozenT [24]

Answer:

15.7 feet

Step-by-step explanation:

What we are looking for here is the perimeter/circumference of the table. The formula for the circumference of a circle is diameter x pi. The diameter is 2x the radius so I did 5 x 3.14, 3.14 being in place for pi. Hope this helps! : )

5 0
3 years ago
Evaluate |5-15|<br><br> A) -10<br><br> B) 10<br><br> C) 20<br><br> D) -20
Oksana_A [137]

Answer:

B) 10

Step-by-step explanation:

|5-15|

Do what is inside the absolute values signs

5-15

-10

|-10|

Absolute value means always positive so take the positive value of -10

10

7 0
3 years ago
Read 2 more answers
38. Evaluate f (3x +4y)dx + (2x --3y)dy where C, a circle of radius two with center at the origin of the xy
lina2011 [118]

It looks like the integral is

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy

where <em>C</em> is the circle of radius 2 centered at the origin.

You can compute the line integral directly by parameterizing <em>C</em>. Let <em>x</em> = 2 cos(<em>t</em> ) and <em>y</em> = 2 sin(<em>t</em> ), with 0 ≤ <em>t</em> ≤ 2<em>π</em>. Then

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \int_0^{2\pi} \left((3x(t)+4y(t))\dfrac{\mathrm dx}{\mathrm dt} + (2x(t)-3y(t))\frac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt \\\\ = \int_0^{2\pi} \big((6\cos(t)+8\sin(t))(-2\sin(t)) + (4\cos(t)-6\sin(t))(2\cos(t))\big)\,\mathrm dt \\\\ = \int_0^{2\pi} (12\cos^2(t)-12\sin^2(t)-24\cos(t)\sin(t)-4)\,\mathrm dt \\\\ = 4 \int_0^{2\pi} (3\cos(2t)-3\sin(2t)-1)\,\mathrm dt = \boxed{-8\pi}

Another way to do this is by applying Green's theorem. The integrand doesn't have any singularities on <em>C</em> nor in the region bounded by <em>C</em>, so

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \iint_D\frac{\partial(2x-3y)}{\partial x}-\frac{\partial(3x+4y)}{\partial y}\,\mathrm dx\,\mathrm dy = -2\iint_D\mathrm dx\,\mathrm dy

where <em>D</em> is the interior of <em>C</em>, i.e. the disk with radius 2 centered at the origin. But this integral is simply -2 times the area of the disk, so we get the same result: -2\times \pi\times2^2 = -8\pi.

3 0
3 years ago
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