Answer:
a) 3.6
b) 1.897
c)0.0273
d) 0.9727
Step-by-step explanation:
Rabies has a rare occurrence and we can assume that events are independent. So, X the count of rabies cases reported in a given week is a Poisson random variable with μ=3.6.
a)
The mean of a Poisson random variable X is μ.
mean=E(X)=μ=3.6.
b)
The standard deviation of a Poisson random variable X is √μ.
standard deviation=S.D(X)=√μ=√3.6=1.897.
c)
The probability for Poisson random variable X can be calculated as
P(X=x)=(e^-μ)(μ^x)/x!
where x=0,1,2,3,...
So,
P(no case of rabies)=P(X=0)=e^-3.6(3.6^0)/0!
P(no case of rabies)=P(X=0)=0.0273.
d)
P(at least one case of rabies)=P(X≥1)=1-P(X<1)=1-P(X=0)
P(at least one case of rabies)=1-0.0273=0.9727
Multiply the amount per dollar offered by a bank, by the number of dollars you want to exchange it all depends on exchange rate they have it at.
I don’t know what I’m solving for so I solved for h and with that it should be h=q/2+m/2
Explanation:
15h-m=13h+q
-13h -13h
———————-
2h-m=q
+m +m
———————-
2h=q+m
/2 /2 /2
———————-
H=q/2+m/2
Between 8 and 10. Because the number graph goes in two's and not in one's, the odd numbers go in between the even numbers.
The answer is c first 2×6= 12 then 12-5=7
then do -7×-2=14 the minus signs cancel
finaly we have two bracket so we multiply both number (7)×(14)=98
