Answer:
113.4g of N2
Explanation:
Step 1:
The balanced equation for the reaction.
N2 + 3H2 —> 2NH3
Step 2:
Determination of the mass of N2 and H2 that reacted from the balanced equation. This is illustrated below:
Molar mass of N2 = 2x14 = 28g/mol
Mass of N2 from the balanced equation = 1 x 28 = 28g
Molar mass of H2 = 2x1 = 2g/mol
Mass of H2 from the balanced equation = 3 x 2 = 6g
From the balanced equation above, 28g of N2 reacted with 6g of H2.
Step 3:
Determination of the mass N2 required to react with 24.3g of H2.
The mass of N2 required to react with 24.3g of H2 can be obtained as follow:
From the balanced equation above, 28g of N2 reacted with 6g of H2.
Therefore, Xg of N2 will react 24.3g of H2 i.e
Xg of N2 = (28 x 24.3)/6
Xg of N2 = 113.4g
Therefore, 113.4g of N2 is required to react completely with 24.3g of H2.
