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saw5 [17]
3 years ago
9

The heaviest known noble gas metal is radon, atomic number 86. part a find the atomic numbers of the as yet undiscovered next tw

o members of the series.
Chemistry
1 answer:
polet [3.4K]3 years ago
6 0
Yuri Oganessian has already discovered the next noble gas at atomic weight 118, (which is 86 plus 32). The next most likely, if ever encountered, should be 150 (which is 118 plus 32) or at 168 (which is 118 plus 32 plus 16).
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Can someone help me check my answers for the mole questions?
Sliva [168]

Answer:

Explanation:

Given data:

Number of particles of phosphorous = 1.2 × 10²⁵

Number of moles = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

Number of particles of phosphorous = 1.2 × 10²⁵ particles

1 mole = 6.022 × 10²³ particles

1.2 × 10²⁵ particles × 1 mole /  6.022 × 10²³ particles

0.1993  × 10² mol

19.93 mole

Q 3:

Given data:

Number of moles of calcium = 0.630 mol

Number of particles = ?

Solution:

The number 6.022 × 10²³ is called Avogadro number.

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ particles of hydrogen

For 0.63 moles:

1 mole = 6.022 × 10²³ particles

0.63 mol × 6.022 × 10²³ particles  / 1 mol

3.79 × 10²³ particles

Q 4:

Given data:

Number of moles = 4 mol

Number of particles = ?

Solution:

The number 6.022 × 10²³ is called Avogadro number.

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ particles of hydrogen

For 4 moles:

1 mole = 6.022 × 10²³ particles

4 mol × 6.022 × 10²³ particles  / 1 mol

24 × 10²³ particles

2.4  × 10²⁴ particles

3 0
3 years ago
To make a 7.21M solution, how many moles of solute will be needed if 12.0 liters of solution is required? (Stoichiometry)
djyliett [7]

Answer:

I think it's 78. I might be wrong I'm not sure.

Explanation:

8 0
3 years ago
How many grams of H2 are needed to produce 13.33g of NH3?
Zanzabum

The reaction to form NH3 is : N2 + 3H2-> 2NH3 12,33g NH3 is 12,33/17,03=0,3 =0,724 moles of NH3 moles NH3. So you need 1,5*0,724 = 1,086 moles H2 1,086*2,016 = 2,189 g of H2 is needed ro form 12,33 g NH3

3 0
3 years ago
If chlorine gas is bubbles through an aqueous solution of sodium iodide,the result is elemental iodine and aqueous sodium chlori
Mrac [35]
The balanced reaction that describes the reaction of chlorine gas and sodium iodide to produce elemental iodine and sodium chloride in aqueous solution is expressed Cl2+2NaI= I2 + 2NaCl. This kind of reaction is called single replacement reaction where the anion, in this case, is only replaced
3 0
3 years ago
An analog and a digital version of an audio signal were copied.
tigry1 [53]

Answer:

a

Explanation:just did the question and I guessed an answer cuz I didnt know it and I got it wrong so its a for a p e x

3 0
3 years ago
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