1) Balanced chemical equation
4NH3(g) + 5O2(g) ---> 4NO(g) + 6H2O(g)
2) State the molar ratios
4 mol NH3 : 5 mol O2 : 4 mol NO : 6 mol H2O
3) Convert 88.9 g of ammonia to moles, using the molar mass
molar mass of NH3 = 14 g/mol + 3 * 1 g/mol = 17 g/mol
number of moles = mass in grams / molar mass = 88.9 g / 17 g/mol = 5.23 mol NH3
4) Make the proportion
4 mol NO / 4 mol NH3 = x / 5.23 mol NH3=> x = 5.23 mol NO
5) Convert 5.23 mol NO to grams
molar mass NO = 14 g/mol + 16g/mol = 30 g/mol
mass = number of moles * molar mass = 5.23 mol * 30 g/mol = 156.9 g ≈ 157 g
Answer: 157 grams
Answer:
water
Acidity and basicity are usually determined in a solvent. The strongest acid in the solvent is always the conjugate acid of the solvent and the strongest base is the conjugate base of the solvent. So, in water, the strongest acid is H3O+ and the strongest base is OH- (conjugate base of water).
The equation is as follows;
2CH3OH(g) = 2CH4(g) + O2(g), ΔH= +252.8 kJ
From the equation; for the reaction to produce 2 moles of methane (32g) an energy of 252.8 kJ is released.
Therefore; for an energy of 82.3 kJ the number of moles that will be produced will be; = (2×82.3)/252.3
= 0.6524 moles
which is equivalent to 0.6524 × 16 = 10.438 g
There, the mass of CH4 produced will be 10.438 g
Answer:
Percentage yield is 41.21%
Explanation:
Equation of reaction,
N₂ + 3H₂ → 2NH₃
Actual NH3 = 6.83g
Mass of N2 = 5.77g
Theoretical yield = ?
5.77g of N2 = 6.83g of NH3
14g of N2 = xg
X = (14 × 6.83) / 5.77
X = 95.62 / 5.77
X = 16.57g of NH3
Theoretical yield of NH3 is 16.57g
Percentage yield = (actual yield / theoretical yield) × 100
% yield = (6.83 / 16.57) × 100
% yield = 0.4121 × 100
% yield = 41.21%
The percentage yield of NH3 is 41.21%
Answer:
positive(cations) and negative(anions)
Explanation:
