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Ivahew [28]
3 years ago
9

WILL GIVE BRAINLIESTWhat is the value of a in the problem 4a-3=Dexplain answer

Mathematics
1 answer:
mixas84 [53]3 years ago
4 0
In this case, you aren't going to get an integer for the value of a, but you can rearrange the equation to equal a.

4a-3=D       add 3 to both sides
4a=D+3      divide both sides by 4
a=(D+3)/4   here's your answer
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What is the geometric mean between 3 and 10
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Answer:

So for the geometric mean, you would multiply the two numbers and put them under a radical

Step-by-step explanation:

3 times 10= 30

=\sqrt{30}

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Whats the area of a square computer screen with 21-inch sides
Sidana [21]
84 Sq inches by 21 x 4
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Determine determine whether the following geometric series converges or diverges. if the series converges find its sum.
Lilit [14]

For starters,

\dfrac{3^k}{4^{k+2}}=\dfrac{3^k}{4^24^k}=\dfrac1{16}\left(\dfrac34\right)^k

Consider the nth partial sum, denoted by S_n:

S_n=\dfrac1{16}\left(\dfrac34\right)+\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\cdots+\dfrac1{16}\left(\dfrac34\right)^n

Multiply both sides by \frac34:

\dfrac34S_n=\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\dfrac1{16}\left(\dfrac34\right)^4+\cdots+\dfrac1{16}\left(\dfrac34\right)^{n+1}

Subtract S_n from this:

\dfrac34S_n-S_n=\dfrac1{16}\left(\dfrac34\right)^{n+1}-\dfrac1{16}\left(\dfrac34\right)

Solve for S_n:

-\dfrac14S_n=\dfrac3{64}\left(\left(\dfrac34\right)^n-1\right)

S_n=\dfrac3{16}\left(1-\left(\dfrac34\right)^n\right)

Now as n\to\infty, the exponential term will converge to 0, since r^n\to0 if 0. This leaves us with

\displaystyle\lim_{n\to\infty}S_n=\lim_{n\to\infty}\sum_{k=1}^n\frac{3^k}{4^{k+2}}=\sum_{k=1}^\infty\frac{3^k}{4^{k+2}}=\frac3{16}

8 0
3 years ago
Read 2 more answers
Use the distance formula to find the distance between each PowerPoint round to the nearest 10th if necessary
natita [175]

Answer:

Step-by-step explanation:

Distance between two points (x_1,y_1) and (x_2,y_2) is given by the formula,

Distance = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

a). A(-6, -4), B(-3, -1)

Distance between A and B = \sqrt{(-6+3)^2+(-4+1)^2}

                                             = \sqrt{9+9}

                                             = 3√2

                                             = 4.2 units

b). C(3.5, 1), D(-4, 2.5)

Distance between C and D = \sqrt{(3.5+4)^2+(1-2.5)^2}

                                              = \sqrt{58.5}

                                              = 7.65

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c). Distance between X(5, -5) and Y(-5, 5)

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                    = \sqrt{200}

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                    = 14.14

                    ≈ 14.1 units

4 0
3 years ago
Among the cast aluminum parts manufactured on a certain day, 90% were flawless, 8% had only a minor flaw, and 2% had major flaws
Andreyy89

Answer:

10% probability that the part has at least one flaw

Step-by-step explanation:

We have these following probabilities:

90% probability of the part being flawless.

8% probability of the part having a minor flaw

2% probability of the part having major flaws.

What is the probability that the part has at least one flaw

Minor or major flaws. So 8% + 2% = 10%

10% probability that the part has at least one flaw

3 0
3 years ago
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