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Anastasy [175]
3 years ago
9

If \\(z_1=3+2i\\) and \\(z_2=4+3i\\) and are complex numbers, find \\(z_1z_2\\)

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0

z_1z_2=(3+2i)(4+3i)=3\cdot4+2i\cdot4+3\cdot3i+2i\cdot3i

z_1z_2=12+8i+9i+6i^2

i^2=-1, so

z_1z_2=12+8i+9i-6=\boxed{6+17i}

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Express 512 as a power of 2.<br> a) 2*8*<br> b) 27*7*<br> c)29*9*<br> d) 210*10*
mote1985 [20]

Answer:

256^2

Step-by-step explanation:

256 power 2 is in a power of 2

7 0
2 years ago
A given line has the equation 10x + 2y = −2.
sergij07 [2.7K]
Firstly, let's convert 10x + 2y = -2 to slope-intercept form (y = mx + b):

10x + 2y = -2
2y = -10x - 2
y = -5x - 2/5

The slope is -5. Parallel lines have the same slope; the question provides the y-int (12), so our equation is:

y = -5x + 12

Hope this helps.
5 0
3 years ago
Read 2 more answers
Evaluate each expression for g = -7 and h = 3 and match it to its value.
Molodets [167]

The given expressions are solved and matched

<h3><u>Solution:</u></h3>

To match the given expressions we need to solve the expressions with the given values of g and h and find their value.

Given that g = -7 and h = 3

\begin{array}{l}{\text { 1) } g+h=-7+3=-4} \\\\ {\text { 2) } g-h=-7-3=-10} \\\\ {\text { 3) } h-g=3+7=10} \\\\ {\text { 4) } g h=-7 \times 3=-21} \\\\ {\text { 5) } g+h^{2}=-7+3^{2}=-7+9=2} \\\\ {\text { 6) } g^{2}-h=(-7)^{2}-3=49-3=46}\end{array}

3 0
3 years ago
Write the first 6 terms of the arithmetic sequence whose first term is 8 and has a common difference of 2
soldier1979 [14.2K]

Answer: The first 6 terms are = 8, 10, 12,14,16,18

Step-by-step explanation:

The NTH term of an Arithmetic Sequence is given as

an = a1 + (n - 1 ) d

where a1 = First term  given as 8 and

d=  common difference given as 2

Therefore  We have that

the first term

an = a1 + (n - 1 ) d = 8+(1-1) 2

a1= 8

second term=

an = a1 + (n - 1 ) d= a2= 8 + (2-1) 2

= 8+ 2(1) = 10

3rd term

an = a1 + (n - 1 ) d= a3= 8 + (3-1) 2

= 8+ 2(2)= 8 + 4=12

4th term

an = a1 + (n - 1 ) d= a4= 8 + (4-1) 2

= 8+ 2(3)= 8+6=14

5th term

an = a1 + (n - 1 ) d= a5= 8 + (5-1) 2

= 8+ 2(4)=8+ 8=16

6th term

an = a1 + (n - 1 ) d= a6= 8 + (6-1) 2

= 8+ 2(5)=8 +10 =18

6 0
3 years ago
I need help with this question !
lidiya [134]

Answer:

3x -2 ≤ 2x +1

3x ≤ 2x +3

x ≤ 3

so its {x|x∈ℝ, x ≤ 3}

7 0
2 years ago
Read 2 more answers
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