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xz_007 [3.2K]
3 years ago
6

Due in 3 mins please help!!!

Mathematics
1 answer:
Korvikt [17]3 years ago
3 0

Answer:

a=100 sq. cm.

Step-by-step explanation:

a= l×w

a=10×10

a=100

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Coefficiants of (2x+y)^4​
sattari [20]

By the binomial theorem,

(2x+y)^4=\displaystyle\sum_{k=0}^4\binom 4k(2x)^{4-k}y^k=\sum_{k=0}^4\binom 4k2^{4-k}x^{4-k}y^k

where

\dbinom nk=\dfrac{n!}{k!(n-k)!}

Then the coefficients of the x^{4-k}y^k terms in the expansion are, in order from k=0 to k=4,

\dbinom 402^{4-0}=1\cdot2^4=16

\dbinom412^{4-1}=4\cdot2^3=32

\dbinom422^{4-2}=6\cdot2^2=24

\dbinom432^{4-3}=4\cdot2^1=8

\dbinom442^{4-4}=1\cdot2^0=1

3 0
3 years ago
What is the sum of the counting numbers 1 - 40
AVprozaik [17]
Simply it as follows:

1 + 39 = 40
2 + 38 = 40 etc

18 + 22 = 40
19 + 21 = 40

There are 19 of these plus 40 itself . . .therefore 20 of them

20 x 40 = 800

And finally the last number not used, 20

Therefore 800 + 20 = 820
5 0
3 years ago
Read 2 more answers
Solve for m: <br> 8(m + 2) = 3(12 - 4m)
Tema [17]

Answer:

m=1

Step-by-step explanation:

step 1: 8(m + 2) = 3(12 - 4m) remove the parentheses

step 2: 8 m + 2 = 3 12 - 4m move the terms

step 3: 8m+ 12m= 36 - 16 collect like terms and calulate

step 4: 20m=20 divide both sides

solution: m=1

3 0
3 years ago
Read 2 more answers
20,10,5, ...<br> Find the 9th term.
iren [92.7K]

Answer:

0.078125.

Step-by-step explanation:

This is a geometric sequence with first term a1 = 20 and common ratio r = 10/20 = 5/10 = 0.5.

nth term = a1 r^(n -1) so here:

9th term = 20(0.5)^(9-1)

= 20(0.5)^8

= 0.078125.

6 0
2 years ago
3(12-3y^2) Help solve this please
HACTEHA [7]
Step 1. <span>Distribute

</span>3*12+3*-3 y^{2}
<span>
Step 2. Simplify </span>3*12 to 36

36+3*-3 y^{2}

Step 3. Simplify 3*-3 y^{2} to -9 y^{2}

36-9 y^{2}

Done! :)
5 0
3 years ago
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