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anastassius [24]
2 years ago
13

sammi is trying to wrap a gift for her brother. the gift fits into a cube-shaped box with a side length of 9 inches. how many sq

uare inches of wrapping paper does she need to cover the box without the paper overlapping? use the formula A=6s2 so that s equals the side length and A equal the surface area
Mathematics
1 answer:
Flauer [41]2 years ago
8 0

Answer:

A=486\ \text{inches}^2

Step-by-step explanation:

The area of a cube shaped box is given by :

A=6s^2

Where

s is the side length and A is the surface area

We have, s = 9 inches

So,

A=6\times (9)^2\\\\A=486\ \text{inches}^2

So, the required area is 486\ \text{inches}^2.

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Answer: Step 1: Reverse the signs of 6x^3-2x + 3 expression.

Step 2: Removing parenthesis

Step 3: Grouping like terms

Step 4: Combing like terms

Step 5: Writing the final expression in standard form

Step-by-step explanation: First expression :6x^3-2x + 3

Second expression : -3x^3+5x^2+4x-7.

We need to subtract 6x^3-2x + 3 from -3x^3+5x^2+4x-7.

Step 1: Reverse the signs of 6x^3-2x + 3 expression.

(-3x^3+5x^2+4x-7)+(-6x3+2x-3)

Step 2: Removing parenthesis

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Step 3: Grouping like terms

[-3x^3) + (-6x^3)] + [4x + 2x] + [(-7) + (-3)] + [5x^2]

Step 4: Combing like terms

-9x^3 + 6x + (-10) + 5x^2

Step 5: Writing the final expression in standard form

-9x^3 + 5x^2 + 6x-10



8 0
3 years ago
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