Answer:
ü=2i+2j+0k
Step-by-step explanation:
The given plane 2x + 2y + 2 = 3 can also be written as:
2x+2y=3-2
2x+2y=1
The general equation for a plane is Ax+By+Cz=D and by definition the normal vector of that plane is n=Ai+Bj+Ck
Where i,j,k are the unit vectors
In order to demostrate that the vector n is normal to the plane, let R1=(a1,b1,c1) and R2=(a2,b2,c2) be two vectors that are in the plane.
If R1 ∈ Ax+By+Cz=D then Aa1+Bb1+Cc1=D
If R2 ∈ Ax+By+Cz=D then Aa2+Bb2+Cc2=D
Therefore, the vector R1R2=R2-R1=(a2-a1)i+(b2-b1)j+(c2-c1)k
You can apply the dot product. <em>If the dot product of the two vectors is zero then the vectors are normal.</em>
So, the vector which components are A,B,C is normal to the plane becase it is normal to any vector contained in the plane.
In this case:
A=2, B=2, C=0
ü=2i+2j+0k
On the 2 quadrant is where it is located
Answer: x=5/3
Step-by-step explanation:
For this problem, we can use teh information given to write out an equation and solve. Let's use x for the unknown number.
5x+5=2x+10
The left side of the equation comes from the part that says "five times a number plus 5". That is modeled above. The right side of the equation comes from "has the same value as twice the number plus 10".
5x+5=2x+10 [subtract both sides by 2x]
3x+5=10 [subtract both sides by 5]
3x=5 [divide both sides by 3]
x=5/3
Now, we have found the unknown number, x=5/3.
We can set up an equation with x as the price of one cup:
4x=0.96
x=0.96/4=0.24
Each cup is $0.24
Hope this helped!