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natka813 [3]
3 years ago
13

The mean of the data set(9,5,y,2,x)is twice the data set (8,x, 4,1,3).What is (y-x)

Mathematics
1 answer:
pantera1 [17]3 years ago
5 0

Answer:

y - x = 16

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u>Step(i)</u>:-

Given data set A  is  9,5,y,2,x

<em>Mean of the Data set A </em>

<em>                          =   </em>\frac{9 + 5 + y + 2 +x}{5}<em></em>

<em>                          = </em>\frac{16 +x+y}{5}<em></em>

<em>Given data set B is 8, x, 4, 1, 3</em>

<em>Mean of the Data set B </em>

                         =   \frac{8+ x+4+1+3}{5}

<u><em>Step(ii):-</em></u>                          

<em>Mean of the Data set A  = 2 X Mean of the Data set B </em>

<em>               </em>\frac{16 +x+y}{5} =  2 X \frac{16+x}{5}<em></em>

<em>On simplification , we get</em>

           16 +x + y = 2( 16 +x)

           16 + x + y = 32 + 2 x

            16 + x + y - 32 - 2 x = 0

            y - x -16 =0

           y - x = 16

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Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
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2k^2 - 3k - 9 = 0

As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
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Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

Hope this Helps! :)
7 0
3 years ago
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