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3 years ago

What is fifty two thousand, fifty two in standard form

Mathematics

2 answers:

solniwko [45]3 years ago

6 0

Fifty two thousand fifty two is equal to 52,052.

True [87]3 years ago

4 0

52,052 don't forget to put the coma

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1.2, 3, 7.5, 18.75, ...

Svetradugi [14.3K]

Answer:

1.2(2.5)x - 1

Step-by-step explanation:

3 0

2 years ago

Points Possible: 1, Points Correct: 0 Given the equation y = x + 9, what is the y -intercept?

-Dominant- [34]

Answer:

Step-by-step explanation:

The equation says y = x + 9

Therefore, y = 9 since x = 0 on the y axis.

Picture of graph also attached :)

8 0

2 years ago

There are two spinners. Each spinner has 10 equal sectors labeled with the numbers 1 through 10.

murzikaleks [220]

Answer:

There are 4 prime numbers from 1 to 10: 2, 3, 5, and 7. This means that there are 4 ways to choose the first outcome. There are 5 composite numbers from 1 to 10: 4, 6, 8, 9, and 10 (1 is just 1). So, you just multiply the two numbers together because each depends on each: 4 * 5 = 20 outcomes.

Step-by-step explanation:

please give me a brainliest answer

8 0

2 years ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

2 years ago

Help my on these two questions plss

Mariana [72]

7. Loan amount = $12000

Monthly payment = $380

Duration of the repayment = 3 years = 3(12) = 36 months.

Total amount Jason repaid = 36 × 380 = 13680

Interest on loan amount = amount repaid - loan amount

= 13680 - 12000

= 1680

Hence, total amount Jason paid in interest on loan = $1680 and the correct option is (D).

8. Loan amount = $35000

Monthly payment = $315

Duration of the repayment = 10 years = 10(12) = 120 months.

Total amount Gerald repaid = 120 × 315 = 37800

Interest on loan amount = amount repaid - loan amount

= 37800 - 35000

= 2800

Hence, total amount Gerald paid in interest on loan = $2800 and the correct option is (B).

3 0

2 years ago