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salantis [7]
4 years ago
9

Reuben would like to buy sports car that cost $35,000 today when he graduates from college in five years if the rate of informat

ion is expected to be 3% per year over the next five years how much wood Ruben expect to pay for a similar sports car in today's dollars
Mathematics
2 answers:
alexandr402 [8]4 years ago
7 0

Answer:

<h2>$40,250</h2>

Step-by-step explanation:

Amount he will pay in the next five years = Principal + Interest

Given Principal =  $35,000

Simple Interest = PRT/100

R is the rate = 3%

T is the time in years = 5years

SI = 35,000 * 3 * 5/100

SI =  $5,250

Amount =  $35,000  +  $5,250

Amount =  $40,250

Ruben will have to pay $40,250 after 5years

Ira Lisetskai [31]4 years ago
5 0

Answer:

Reuben would pay $40574.59 in 5 years time

Step-by-step explanation:

The present value of the car, P = $35,000

Rate per year, R = 3% = 0.03 (Note that the rate is given per year and not for the whole 5 years, this means that the rate cannot be used over a period of 5 years)

Amount = P + RP = P (1 + R) = P ( 1+0.03)

Amount = 1.03P

Total time = 5 yrs

After year 1:

A = 1.03 * 35000 = $36,050

After year 2:

A = 1.03 * 36050 = $37,131.5

After year 3:

A = 1.03 * 37131.5 = $38,245.445

After year 4:

A = 1.03 * 38,245.445 = $39,392.808

After year 5:

A = 1.03 * 39,392.808 = $40574.59

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Answer:

C.

Step-by-step explanation:

All living things are made of one or more cells.

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3 0
3 years ago
Two random samples are taken from private and public universities
kati45 [8]

Answer:

Step-by-step explanation:

For private Institutions,

n = 20

Mean, x1 = (43120 + 28190 + 34490 + 20893 + 42984 + 34750 + 44897 + 32198 + 18432 + 33981 + 29498 + 31980 + 22764 + 54190 + 37756 + 30129 + 33980 + 47909 + 32200 + 38120)/20 = 34623.05

Standard deviation = √(summation(x - mean)²/n

Summation(x - mean)² = (43120 - 34623.05)^2+ (28190 - 34623.05)^2 + (34490 - 34623.05)^2 + (20893 - 34623.05)^2 + (42984 - 34623.05)^2 + (34750 - 34623.05)^2 + (44897 - 34623.05)^2 + (32198 - 34623.05)^2 + (18432 - 34623.05)^2 + (33981 - 34623.05)^2 + (29498 - 34623.05)^2 + (31980 - 34623.05)^2 + (22764 - 34623.05)^2 + (54190 - 34623.05)^2 + (37756 - 34623.05)^2 + (30129 - 34623.05)^2 + (33980 - 34623.05)^2 + (47909 - 34623.05)^2 + (32200 - 34623.05)^2 + (38120 - 34623.05)^2 = 1527829234.95

Standard deviation = √(1527829234.95/20

s1 = 8740.22

For public Institutions,

n = 20

Mean, x2 = (25469 + 19450 + 18347 + 28560 + 32592 + 21871 + 24120 + 27450 + 29100 + 21870 + 22650 + 29143 + 25379 + 23450 + 23871 + 28745 + 30120 + 21190 + 21540 + 26346)/20 = 25063.15

Summation(x - mean)² = (25469 - 25063.15)^2+ (19450 - 25063.15)^2 + (18347 - 25063.15)^2 + (28560 - 25063.15)^2 + (32592 - 25063.15)^2 + (21871 - 25063.15)^2 + (24120 - 25063.15)^2 + (27450 - 25063.15)^2 + (29100 - 25063.15)^2 + (21870 - 25063.15)^2 + (22650 - 25063.15)^2 + (29143 - 25063.15)^2 + (25379 - 25063.15)^2 + (23450 - 25063.15)^2 + (23871 - 25063.15)^2 + (28745 - 25063.15)^2 + (30120 - 25063.15)^2 + (21190 - 25063.15)^2 + (21540 - 25063.15)^2 + (26346 - 25063.15)^2 = 1527829234.95

Standard deviation = √(283738188.55/20

s2 = 3766.55

This is a test of 2 independent groups. Let μ1 be the mean out-of-state tuition for private institutions and μ2 be the mean out-of-state tuition for public institutions.

The random variable is μ1 - μ2 = difference in the mean out-of-state tuition for private institutions and the mean out-of-state tuition for public institutions.

We would set up the hypothesis. The correct option is

-B. H0: μ1 = μ2 ; H1: μ1 > μ2

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

t = (34623.05 - 25063.15)/√(8740.22²/20 + 3766.55²/20)

t = 9559.9/2128.12528473889

t = 4.49

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [8740.22²/20 + 3766.55²/20]²/[(1/20 - 1)(8740.22²/20)² + (1/20 - 1)(3766.55²/20)²] = 20511091253953.727/794331719568.7114

df = 26

We would determine the probability value from the t test calculator. It becomes

p value = 0.000065

Since alpha, 0.01 > than the p value, 0.000065, then we would reject the null hypothesis. Therefore, at 1% significance level, the mean out-of-state tuition for private institutions is statistically significantly higher than public institutions.

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3 years ago
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3 years ago
The thickness of a quarter is approximately 2 millimeters. How many quarters would you need to make a two kilometer high pile? a
Romashka-Z-Leto [24]

We need 1,000,000 quaters to make a two kilometer pile

<em><u>Solution:</u></em>

The thickness of a quarter is approximately 2 millimeters

We need to find the quarters needed to make two kilometer high pile

Let us first convert 2 km to millimeters

<em><u>Use the conversion factor</u></em>

1 kilometer = 1000000 millimeters

Therefore,

2 kilometer = 2 x 1000000 = 2000000 millimeters

We need 2,000,000 mm to make a 2 km pile

Given that, Each quarter is 2 millimeters thick

thickness of quarter = 2 millimeters

<em><u>Divide the total milimetres by the thickness of a quarter</u></em>

\rightarrow \frac{2000000}{2} = 1000000

Thus we need 1,000,000 quaters to make a two kilometer pile

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4 years ago
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