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3 years ago

HELP ME PLEASE

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

8 0

Answer:

Repeats itself

Has a minimum or maximum

Multiplying by the same number

Step-by-step explanation:

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Given that n is an integer and 0 < 4n <30, what is the sum of all possible integer values of n

Anvisha [2.4K]

n can be all the way upto 7 as 8 x4 = 32 which is higher than 30. The lowest possible diggit is 1.

n = 1, 2, 3, 4, 5, 6, 7

1 + 2 + 3 + 4 + 5 + 6 + 7 = 28

⭐ Answered by Foxzy0⭐

⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

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3 years ago

A town was concerned about the growing number of harbor seals in their town's bay. They tagged 15 seals and sent them back into

Zinaida [17]

Answer:

im thinking 200 seals

Step-by-step explanation:

i don't have time sorry but you are welcome

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A new car is purchased for 22300 dollars. The value of the car depreciates at 7.5% per year. To the nearest year, how long will

Slav-nsk [51]

you would have to wait at least a couple of years.

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Simplify 9a^3 b^5 divided by 3ab^2

SCORPION-xisa [38]

When dividing this expression, you have to remember two rules:

<span>1. </span>In dividing constants, you divide it just like the normal division of number.

<span>2. </span>In dividing variables, you have to subtract the exponent of the denominator to the exponent of the denominator.

9a^3b^5 / 3ab^2

3a^(3-1)b^(5-2)

3a^2b^3

4 0

3 years ago

A sample of 64 was taken from a population, with the mean of the sample being 119 and the standard deviation of the sample being

Fofino [41]

We have the sample size, sample mean and the sample standard deviation. Since the population standard deviation is not know, we will use t-distribution to find the confidence interval.

The critical t value for 95% confidence interval and 63 degrees of freedom is 1.998.

The 95% confidence for the population mean will be:

$(119-1.998 *\frac{16}{ \sqrt{64} } ,119+1.998 *\frac{16}{ \sqrt{64} }) \\ \\ 
=(115.004, 122.996) \\ \\=(115,123)$

Thus, the 95% confidence interval for the population mean will be (115,123)

So, option A is the correct answer

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3 years ago