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BaLLatris [955]
3 years ago
10

The legal permitted speed limit for all vehicles near a school zone is

Mathematics
2 answers:
Alenkasestr [34]3 years ago
8 0
C. 25 miles per hour
Sphinxa [80]3 years ago
4 0
Where I'm from, it's 20 mph. So, C
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(r-3)(r-1)<br> Help me please!!!
madreJ [45]

Answer:

= r²−4r+3

Step-by-step explanation:

(r - 3) (r - 1)

(r x r) + (r x -1) + (-3 x r) + (-3 x -1)

r² + - r - 3r + 3

= r²−4r+3

5 0
3 years ago
How do it do this ????
V125BC [204]
Because he drove 1542.75 miles in 3 days, you would have to divide 1542.75 by 3 to figure out how many miles he drove in one day.

1542.75/3 = 514.25

Then to figure out how many miles he drove per hour, you would divide 514.25 by 8.5, which is the same as 8 1/2 hours.

514.25/8.5 = 60.5

So the answer is 60.5 mph
4 0
3 years ago
What is the explicit formula for this situation?
emmasim [6.3K]

Answer:

D

Step-by-step explanation:

i did it with eliminating choices

3 0
3 years ago
A jug has a maximum capacity of 14 liters. is filled to 60% of its capacity, and then poured out at a rate of 60 mL/s. Which of
ZanzabumX [31]

Answer:

W(x) = 3.4 L - (25/1000)(L/s)*x

Step-by-step explanation:

          it a tip

W(x) = 3.4 L - (25/1000)(L/s)*x

The maximum of the jug is 4 L.

now, the jug is 85% filled, then the amount of water in the jug is:

(85%/100%)*4L = 0.85*4L = 3.4L

Now, we pour 25 mL each second, so we could write a linear equation as:

W(x) = 3.4L - (25ml/s)*x

where x is the number of seconds that passed since the beginning,

But we want to write this in Liters, we have that:

1L = 1000mL.

Then 1mL = (1/1000) L

then we can write 25 mL as:

25m L = 25*(1/1000) L = (25/1000) L

Then we can write the equation as

W(x) = 3.4 L - (25/1000)(L/s)*x

which is the amount of water remaining in the jug after x seconds.

7 0
3 years ago
Choose a system of equations with the same solution as the following system:
Lina20 [59]

Answer:

Option A.

Step-by-step explanation:

We are given 6x+2y =-6 ......(1) and 3x-4y=-18 .....(2)

Solving equations (1) and (2) we get

12x+3x =-30, ⇒x= -2 and from equation (1), 2y= -6-6(-2) =6, ⇒ y=3

Therefore, the solution for the given set of equations is x= -2 and y=3

A) Solving the equations 8x+4y = -4 ....... (3)and 17x+2y =-28, we get  

8x -34x = -4 -(-56) =52, ⇒-26x =52, ⇒x=-2 and from equation )(3), we get -16+4y =-4, ⇒ y=3

Therefore, the solution x=-2 and y =3 match with the original solution.

B)Solving the equations 12x + 4y = 12 ....... (4)and 21x + 2y = −36, we get  

12x -42x = 12 -(-72) =84, ⇒-30x =84, ⇒x=-84/30.

Therefore, the solution x=-84/30 does not match with the original solution.

C) Solving the equations 6x + 8y = −36 ....... (4) and 15x + 6y = −60, we get 18x -60x = -108 -(-240) =132, ⇒-42x =132, ⇒x=-132/42

Therefore, the solution x=--3  do not match with the original solution.

D) Solving the equations 6x + y = 15 ....... (5) and 15x − y = −9, we get 6x +15x = 6, ⇒21x =6, ⇒x=2/7  

Therefore, the solution x=2/7  do not match with the original solution.

Therefore, option A) will have the same solution. (Answer)

4 0
3 years ago
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