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3 years ago

11

Fractions, Decimals, and Percents

1 answer:

KatRina [158]3 years ago

8 0

Answer:

Step-by-step explanation:

13.84%,0.84

14.10,12,12,14,15,17,20.Median is 14.Mode is 12.

15.Mean so add 18+19+20=57.57/3 =19.

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Find a quadratic polynomial with integer coefficients which has x = 2/9, ± SQRT23/9 as its real zeros.

melomori [17]

Answer:

The quadratic polynomial with integer coefficients is $y = 81\cdot x^{2}-36\cdot x -19$ .

Step-by-step explanation:

Statement is incorrectly written. Correct form is described below:

<em>Find a quadratic polynomial with integer coefficients which has the following real zeros: </em> $x = \frac{2}{9}\pm \frac{\sqrt{23}}{9}$ <em>. </em>

Let be $r_{1} = \frac{2}{9}+\frac{\sqrt{23}}{9}$ and $r_{2} = \frac{2}{9}-\frac{\sqrt{23}}{9}$ roots of the quadratic function. By Algebra we know that:

$y = (x-r_{1})\cdot (x-r_{2}) = x^{2}-(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2}$ (1)

Then, the quadratic polynomial is:

$y = x^{2}-\frac{4}{9}\cdot x -\frac{19}{81}$

$y = 81\cdot x^{2}-36\cdot x -19$

The quadratic polynomial with integer coefficients is $y = 81\cdot x^{2}-36\cdot x -19$ .

5 0

3 years ago

What is 46+8-(4x15)+9

sergeinik [125]

535 would be your answer

3 0

4 years ago

Read 2 more answers

Twenty to one meaning time

Nadya [2.5K]

Answer: 20 minutes until 1 o'clock so it would be 12:40

Step-by-step explanation:

3 0

2 years ago

Choose the equation that represents the graph below: (1 point) Graph of a line passing through points 0 comma 6 and 9 comma 0 y

aleksklad [387]

Answer:

Option C is correct.

Equation of a line $y=\frac{-2}{3}x+6$ passing through (0,6) and (9,0).

Explanation:

Given the two points (0, 6) and (9 ,0).

To find the equation for the given two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is,

$y-y_{1}=m(x-x_{1})$ ; where m is the slope and is given by:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

First find the slope m:

$m=\frac{0-6}{9-0} =\frac{-6}{9} =\frac{-2}{3}$

Substitute this value in equation of line:

$y-6=\frac{-2}{3} (x-0)$ or

$y-6=\frac{-2}{3} x$

⇒ $y=\frac{-2}{3}x+6$

Therefore, the equation for the given point is: $y=\frac{-2}{3}x+6$

7 0

3 years ago

Complete the square and write in function form f(x)=x^2+5x+3

Over [174]

F(x) = x^2 +5x + 3

= (x + 2.5)^2 - 6.25 + 3

= (x + 2.5)^2 - 3.25

That is vertex form. I am not sure what you mean by function form

6 0

3 years ago