Answer:
Heyy
Step-by-step explanation:
△ABC is a right angled triangle and right angle at B
sinA=
AC
BC
, cosA=
AC
AB
⟹sinA+cosA=
AC
BC
+
AC
AB
=
AC
BC+AB
[We know that sum of two sides of a triangle is greater than the third side]
⟹sinA+cosA>
AC
AC
=1
Hence, sinA+cosA>1
-3 (x - 5) - 8 (y + 2) + (-3) (6 - 4b)
First, simplify your brackets. / Your problem should look like: -3 (x - 5) - 8 (y + 2) + -3 (6 - 4b)
Second, simplify. / Your problem should look like: -3 (x - 5) - 8 (y + 2) - 3 (b - 4b)
Third, expand your problem. / Your problem should look like: -3x + 15 - 8y - 16 - 18 + 12b
Fourth, simplify. / Your problem should look like: -3x - 8y + 12b - 19
Answer: -3x - 8y + 12b - 19 (D)
Do you have a picture to go with it?
Answer:
done
Step-by-step explanation:
I have installed it
